CODEWITHSUNDEEP
javaexceptiontry-catch
I2obiN
I2obiN

Reputation: 309

(Java) Unable to catch an Exception

I'm a beginner with Java and was attempting to catch the exception 'InputMismatchException'. Below is my code, I hope it is easy to read, apologies in advance if it's not formatted well. It builds fine and executes, but if I input a character for example the 'catch' doesn't function and the error comes up;

"Exception in thread "main" java.util.InputMismatchException"

I believe everything else in the code works fine including the 'try', and I don't have anything going in the catch other than a System.out.print command.

import java.util.*; // imports

public class w4q1

    {
        public static void main(String[] args)
        {
            Scanner user_input = new Scanner( System.in ); // declaring Scanner util
                System.out.print("Please enter an integer: \n"); // Asks for input
                int d = user_input.nextInt();

        while (d > 0 || d < 0) // start of while loop, in the event of anything other than zero entered
        {
            try {

                    if (d < 0) // if statements
                    {
                    System.out.print("The integer " + d + " is negative\n");
                    break;
                    }

                            else if (d > 0)
                            {
                            System.out.print("The integer " + d + " is positive\n");
                            break;
                            }

                                else 
                                {
                                System.out.print("You have not entered an integer\n");
                                break;
                                }

                }

                catch (InputMismatchException e) // Error message for letters/characters and decimals
                    {
                        System.out.print("You have entered an incorrect value, please restart the program\n");
                    }



        }

        if (d == 0)
            {
            System.out.print("A zero has been entered\n");
            }

        }
    }

Upvotes: 0

Views: 1991

Answers (3)

hhsh
hhsh

Reputation: 26

Put a try-catch block around this code

int d = user_input.nextInt();

and by so doing ,you also need to change the current code a little bit to make it OK. Good Luck !

Upvotes: 0

Aaron T
Aaron T

Reputation: 151

If indeed the exception is not getting caught, then the resulting stack trace should show you the actual line of code which threw the exception. Looking at the code, I'm going to guess that this is where the exception occurs:

 user_input.nextInt();

I would recommend you look at the stack trace and see if you can confirm this.

Upvotes: 0

rgettman
rgettman

Reputation: 178243

If you are still receiving an InputMismatchException even though you have a try-catch block, then the exception must be coming from somewhere outside of your try-catch block.

Look at what else outside the try-catch block can throw an InputMismatchException and put a try-catch block around that statement, or expand your existing try-catch block to include that statement.

Upvotes: 1

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