Reputation: 462
I got a log from remote linux computer. It looks like:
2013-10-23T08:19:05+0300 Last login: Wed Oct 23 08:17:38 EEST 2013 from 10.9.167.55 on pts/0
2013-10-23T08:19:05+0300 Last login: Wed Oct 23 08:19:05 2013 from 10.9.167.55^M
2013-10-23T08:19:07+0300 ^[[?1034h-bash-4.1$ date
2013-10-23T08:19:07+0300 Wed Oct 23 08:19:07 EEST 2013
2013-10-23T08:19:08+0300 -bash-4.1$ ls
2013-10-23T08:19:08+0300 ^[[0m^[[01;34m99^[[0m #avail.info ^[[01;34mgmoTemp^[[0m raml21.dtd SNMP4JTestAgentBC.cfg
2013-10-23T08:19:08+0300 an_mainHost_localhost_20131023081654000136.xml #avail.info~ gsh.txt ^[[01;34mresults^[[0m
2013-10-23T08:19:09+0300 ^[[m-bash-4.1$ exit
2013-10-23T08:19:09+0300 logout
But it should be:
Last login: Wed Oct 23 08:17:38 EEST 2013 from 10.9.167.55 on pts/0
Last login: Wed Oct 23 08:19:05 2013 from 10.9.167.55
-bash-4.1$ date
Wed Oct 23 08:19:07 EEST 2013
-bash-4.1$ ls
99 #avail.info gmoTemp raml21.dtd SNMP4JTestAgentBC.cfg
an_mainHost_localhost_20131023081654000136.xml #avail.info~ gsh.txt results
-bash-4.1$ exit
logout
The messy codes are terminal control escape sequences, you can use command "infocmp xterm" and "man terminfo" to get more details.
My question is how can I remove these terminal control escape sequences in the file?
Thanks a lot!
Upvotes: 4
Views: 2860
Reputation: 10039
i use a pipe or direct sed like this
sed 's/[^[:print:]]\[[^a-zA-Z]*[a-zA-Z]//g' YourFile
Upvotes: 4
Reputation: 462
I solved this issue using lots of regular expressions according to http://invisible-island.net/xterm/ctlseqs/ctlseqs.html
Upvotes: 0
Reputation: 41
Simple way to remove most parts of the control character is using the command below in vim:
:%s/<escape-key>\[[0-9;]*m/ /g
Press Ctrl+V followed by esc-key for the <escape-key>
character above. Everything else is the same literal key as in your keyboard.
Upvotes: 4