Reputation: 546
I am writing a greedy algorithm (Python 3.x.x) for a 'jewel heist'. Given a series of jewels and values, the program grabs the most valuable jewel that it can fit in it's bag without going over the bag weight limit. I've got three test cases here, and it works perfectly for two of them.
Each test case is written in the same way: first line is the bag weight limit, all lines following are tuples(weight, value).
Sample Case 1 (works):
10
3 4
2 3
1 1
Sample Case 2 (doesn't work):
575
125 3000
50 100
500 6000
25 30
Code:
def take_input(infile):
f_open = open(infile, 'r')
lines = []
for line in f_open:
lines.append(line.strip())
f_open.close()
return lines
def set_weight(weight):
bag_weight = weight
return bag_weight
def jewel_list(lines):
jewels = []
for item in lines:
jewels.append(item.split())
jewels = sorted(jewels, reverse= True)
jewel_dict = {}
for item in jewels:
jewel_dict[item[1]] = item[0]
return jewel_dict
def greedy_grab(weight_max, jewels):
#first, we get a list of values
values = []
weights = []
for keys in jewels:
weights.append(jewels[keys])
for item in jewels.keys():
values.append(item)
values = sorted(values, reverse= True)
#then, we start working
max = int(weight_max)
running = 0
i = 0
grabbed_list = []
string = ''
total_haul = 0
# pick the most valuable item first. Pick as many of them as you can.
# Then, the next, all the way through.
while running < max:
next_add = int(jewels[values[i]])
if (running + next_add) > max:
i += 1
else:
running += next_add
grabbed_list.append(values[i])
for item in grabbed_list:
total_haul += int(item)
string = "The greedy approach would steal $" + str(total_haul) + " of
jewels."
return string
infile = "JT_test2.txt"
lines = take_input(infile)
#set the bag weight with the first line from the input
bag_max = set_weight(lines[0])
#once we set bag weight, we don't need it anymore
lines.pop(0)
#generate a list of jewels in a dictionary by weight, value
value_list = jewel_list(lines)
#run the greedy approach
print(greedy_grab(bag_max, value_list))
Does anyone have any clues why it wouldn't work for case 2? Your help is greatly appreciated. EDIT: The expected outcome for case 2 is $6130. I seem to get $6090.
Upvotes: 3
Views: 16344
Reputation: 113975
In [237]: %paste
def greedy(infilepath):
with open(infilepath) as infile:
capacity = int(infile.readline().strip())
items = [map(int, line.strip().split()) for line in infile]
bag = []
items.sort(key=operator.itemgetter(0))
while capacity and items:
if items[-1][0] <= capacity:
bag.append(items[-1])
capacity -= items[-1][0]
items.pop()
return bag
## -- End pasted text --
In [238]: sum(map(operator.itemgetter(1), greedy("JT_test1.txt")))
Out[238]: 8
In [239]: sum(map(operator.itemgetter(1), greedy("JT_test2.txt")))
Out[239]: 6130
Upvotes: 1
Reputation: 5784
I think in this piece of code i
has to be incremented on the else side too
while running < max:
next_add = int(jewels[values[i]])
if (running + next_add) > max:
i += 1
else:
running += next_add
grabbed_list.append(values[i])
i += 1 #here
this and @iblazevic's answer explains why it behaves this way
Upvotes: 0
Reputation: 2733
Your dictionary keys are strings, not integers so they are sorted like string when you try to sort them. So you would get:
['6000', '3000', '30', '100']
instead wanted:
['6000', '3000', '100', '30']
Change this function to be like this and to have integer keys:
def jewel_list(lines):
jewels = []
for item in lines:
jewels.append(item.split())
jewels = sorted(jewels, reverse= True)
jewel_dict = {}
for item in jewels:
jewel_dict[int(item[1])] = item[0] # changed line
return jewel_dict
When you change this it will give you:
The greedy approach would steal $6130 of jewels.
Upvotes: 3