CODEWITHSUNDEEP
pythonhtmlbeautifulsoup
vjgaero
vjgaero

Reputation: 57

Getting 'name' attributes with Beautiful Soup

from bs4 import BeautifulSoup

source_code = """<a href="#" name="One"></a>
                 <a href="#" name="Two"></a>"""

soup = BeautifulSoup(source_code)

print soup.a['name']   #prints 'One'

Using BeautifulSoup, i can grab the first name attribute which is one, but i am not sure how i can print the second, which is Two

Anyone able to help me out?

Upvotes: 2

Views: 5876

Answers (3)

Vicent
Vicent

Reputation: 5452

You should read the documentation. There you can see that soup.find_all returns a list so you can iterate over the list and, for each element, extract the tag you are looking for. So you should do something like (not tested here):

from bs4 import BeautifulSoup
soup = BeautifulSoup(source_code)
for item in soup.find_all('a'):
    print item['name']

Upvotes: 4

Sudipta
Sudipta

Reputation: 4971

This will give you all the tags of "a":

>>> from BeautifulSoup import BeautifulSoup
>>> aTags = BeautifulSoup(source_code).findAll('a')
>>> for tag in aTags: print tag["name"]
... 
One
Two

Upvotes: 1

Delan Azabani
Delan Azabani

Reputation: 81432

To get any a child element other than the first, use find_all. For the second a tag:

print soup.find_all('a', recursive=False)[1]['name']

To stay on the same level and avoid a deep search, pass the argument: recursive=False

Upvotes: 1

Related Questions