CODEWITHSUNDEEP
xmlxslt
jj.
jj.

Reputation: 51

XML and XSL files

I've got 4 different XML files which I want to join to make one file. How can I do that?

Each file contains a parent and at least 4 children. Parents are called genre 1,2,3,4 and the children are artist, name, etc. Each file is shown in an HTML table.

Can someone shed some light on this?

Upvotes: 0

Views: 116

Answers (2)

Robert Rossney
Robert Rossney

Reputation: 96702

This XSLT template will do exactly what you've said you want done:

<xsl:template match="/">
   <output>
      <xsl:copy-of select="document('file1.xml')"/>
      <xsl:copy-of select="document('file2.xml')"/>
      <xsl:copy-of select="document('file3.xml')"/>
      <xsl:copy-of select="document('file4.xml')"/>
   </output>
</xsl:template>

If this isn't the right answer, add some more detail to your question.

Upvotes: 0

Matijs
Matijs

Reputation: 2553

Use the XSL document() function.

$d1 = document('doc1.xml'), document('doc2.xml'), ...

The comma's combine the loaded elements into a single sequence (at least in XSL 2, not sure about 1).

If you want the sequence of items within the genre tags use:

$d1 = document('doc1.xml')/genre, document('doc2.xml')/genre, ...

Upvotes: 1

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