Reputation: 490
Currently, I am passing name as a parameter and fetching the result like screen_name
, location
, extended_url
, display_url
.. etc.
My query is like this
$tweets = $twitter->get('https://api.twitter.com/1.1/users/search.json?q=ABC');
Can you please help me in passing display_url as a parameter and fetch the data from it. Like
$tweets = $twitter->get('https://api.twitter.com/1.1/users/search.json?display_url=abc.com');
If I pass my url like this, I am getting error like
stdClass Object
(
[errors] => Array
(
[0] => stdClass Object
(
[code] => 25
[message] => Query parameters are missing.
)
)
)
Please help me in this.Thanks in advance!
Upvotes: 1
Views: 893
Reputation: 3163
display_url
can't be used in the search API, read here:
https://dev.twitter.com/docs/api/1.1/get/search/tweets
Why not do a q=
search on your website?
Upvotes: 3