CODEWITHSUNDEEP
linuxbash
muradin
muradin

Reputation: 1277

bash condition with regular expression

I'm going to learn bash programming. I just wrote a simple script in order to read numbers from input stream and check them to be in valid numerical format using regular expression. in fact script should take input until the input be nonnumerical. but it doesn't work properly.

code:

i=0
echo "plz enter number in valid format: " 

while true
do
        read input

        if  [[ $input =~ *[^0-9]* ]]; then
                echo "YOU DIDN'T ENTER A VALID NUMBER"
                break
        else
                arr[$i]=$input
                echo $input >> inputnums

        fi
done

when i enter a number or character condition is true. I mean i have echo "message" in output.

Upvotes: 1

Views: 304

Answers (2)

dinox0r
dinox0r

Reputation: 16039

Remove the * from the regex:

#!/bin/bash

i=0
echo "plz enter number in valid format: " 

while true
do
    read input

    if  [[ $input =~ ^[^0-9]+$ ]]; then
        echo "YOU DIDN'T ENTER A VALID NUMBER"
        break
    else
        arr[$i]=$input
        echo $input 
    fi
done

Upvotes: 1

anubhava
anubhava

Reputation: 785146

You're mixing shell globing with regex, change your if condition to:

if  [[ $input =~ [^0-9] ]]; then

regex should use .* not * as used by shell shell glob.

Upvotes: 3

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