CODEWITHSUNDEEP
c#
user1889838
user1889838

Reputation: 343

Convert from string to int in c# Using Convert.ToInt32

I have a simple code in c# that converts a string into int

int i = Convert.ToInt32(aTestRecord.aMecProp);

aTestRecord.aMecProp is of string. The test I am running, during that it has values of 1.15 in string.

but above line throws error saying that input string wasn't in a format!

I don't understand why?

I am using VS 2008 c#

Upvotes: 0

Views: 1944

Answers (8)

seyyed mahdi mousavi
seyyed mahdi mousavi

Reputation: 41

ok I think this is 

float d = Convert.ToSingle(aTestRecord.aMecProp);

Upvotes: 0

Tim S
Tim S

Reputation: 2329

Do you need a C# equivalent for the JavaScript parseInt function? I have used this one on occasion:

public int? ParseInt(string value)
{
    // Match any digits at the beginning of the string with an optional
    // character for the sign value.
    var match = Regex.Match(value, @"^-?\d+");

    if(match.Success)
        return Convert.ToInt32(match.Value);
    else
        return null; // Because C# does not have NaN
}

...

var int1 = ParseInt("1.15"); // returns 1
var int2 = ParseInt("123abc456"); // returns 123
var int3 = ParseInt("abc"); // returns null
var int4 = ParseInt("123"); // returns 123
var int5 = ParseInt("-1.15"); // returns -1
var int6 = ParseInt("abc123"); // returns null

Upvotes: 0

Bhavesh Kachhadiya
Bhavesh Kachhadiya

Reputation: 3972

Just try this,

Int32 result =0;
Int32.TryParse(aTestRecord.aMecProp, out result);

Upvotes: 0

kunal
kunal

Reputation: 966

You can convert to double and then typecast it

string str = "1.15";
int val = (int)Convert.ToDouble(str);

Upvotes: 0

Felipe Oriani
Felipe Oriani

Reputation: 38638

That is because 1.xx is not a integer valid value. You could truncate before converting to Int32, for sample:

int result = (int)(Math.Truncate(double.Parse(aTestRecord.aMecProp)* value) / 100);

Upvotes: 1

Ray
Ray

Reputation: 8881

An integer can only represent strings without a decimal part. 1.15 contains a decimal part of 0.15. You have to convert it into a float to keep the decimal part and correctly parse it:

float f = Convert.ToSingle(aTestRecord.aMecProp);

Upvotes: 1

Nickon
Nickon

Reputation: 10156

Try this:

double i = Convert.ToDouble(aTestRecord.aMecProp);

Or if you want the integer part:

int i = (int) Convert.Double(aTestRecord.aMecProp);

Upvotes: 0

Jonesopolis
Jonesopolis

Reputation: 25370

if you are trying to validate that a string is an integer, use TryParse()

int i;
if (int.TryParse(aTestRecord.aMecProp, out i))
{

}

i will get assigned if TryParse() is successful

Upvotes: 0

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