Reputation: 19
I've got this expression and I believe I have the circuit drawn out correctly however I think the truth table for it is a trick question. There is 4 inputs and 2 of them are A and the other 2 are B and C. Here is what I've drawn out:
Here's what I've done for the truth table.
Upvotes: 0
Views: 184
Reputation: 111521
Your logic expression can be simplified using Boolean Algebra.
Start with the given logic expression:
(ab + ac)'
Factor out a
:
(a(b + c))'
Apply De Morgan's law for negation of a conjunction:
a' + (b + c)'
Apply De Morgan's law for negation of a disjunction:
a' + b'c'
Therefore, output is true:
a
is false, ORb
is false AND c
is falseHere is your truth table with corrections:
Upvotes: 2
Reputation: 11209
A false, output true (regardless of B and C) B and C false, output true (regardless of A) Your truth table is not correct.
Upvotes: 0