Reputation: 1565
What I want to do is to execute a function automatically every time BEFORE ANY function is executed in JS, regardless if it's a custom or native function if possible.
ie.
whatIWant(functionName){
return console.log('called before '+functionName);
}
function blah(){
return console.log('called blah');
}
function meh(){
return console.log('called meh');
}
alert('woot');
blah();
//will output :
//called before blah
//called blah
meh();
//will output :
//called before meh
//called meh
alert();
//will output :
//called before alert
//will pop up dialog: woot
I do not want to do the following:
Function.prototype.onBefore = function(){};
blah.onBefore();
is it even possible to do what I am asking for? any suggestions, read, or w/e?
Thanks in advance.
Upvotes: 1
Views: 555
Reputation: 1565
what do you guys think about this solution? :)
function bleh(){
console.log('exe a');
}
function limitFn(fn,n) {
var limit = n ;
var counter = 1 ;
var fnName = fn.toString();
fnName = fnName.substr('function '.length);
fnName = fnName.substr(0, fnName.indexOf('('));
return function(){
if(counter <= limit) {
console.log(counter + ' call before ' + fnName + ' limit ' + limit);
counter++;
fn();
} else {
console.log('limit of ' + limit + ' exes reached') ;
}
};
}
limited = limitFn(bleh,2);
limited();
limited();
limited();
limited();
Upvotes: 1
Reputation: 456
What about just providing your function as a callback to whatIWant like this:
function whatIWant(fn) {
var fnName = fn.toString();
fnName = fnName.substr('function '.length);
fnName = fnName.substr(0, fnName.indexOf('('));
console.log('called before ' + fnName);
fn();
}
function meh() {
console.log('called meh');
}
function blah() {
console.log('called blah');
}
whatIWant(meh);
whatIWant(blah);
whatIWant(alert)
Upvotes: 1