Reputation: 630
Okay. So what I need to do is to initialize a ViewModel
using a constructor. The problem is I can't create the constructor due lack of knowledge. I'm new to MVVM
(or c# in general for that matter) and had to get some help to implement this code:
public class ViewModel
{
private static ViewModel instance = new ViewModel();
public static ViewModel Instance
{
get
{
return instance;
}
}
}
However, I fail to create a constructor to place this code.
DataContext = ViewModel.Instance
It is meant to go into two different pages to pass a value between TextBoxes
.
I'm also confused as to whether I should put the ViewModel
in both the main window and the page or in just one of the two.
So, anyone can help?
Upvotes: 1
Views: 2424
Reputation: 347
If you or anybody else, who's new to the MVVM, gets stuck here, for example at the "INotifyPropertyChanged could not be found". I recommend trying some example-MVVM's or tutorials.
Some I found useful:
Upvotes: 0
Reputation: 6159
Follow this pattern:
This part is how your model classes should look like, Even if you use entity framework to create your model they inherit INPC.. so all good.
public class Model_A : INotifyPropertyChanged
{
// list of properties...
public string FirstName {get; set;}
public string LastName {get; set;}
// etc...
}
each view model is a subset of information to be viewed, so you can have many view models for the same model class, notice that in case your make the call to the parameter-less c-tor you get auto instance of a mock model to be used in the view model.
public class ViewModel_A1 : INotifyPropertyChanged
{
public Model_A instance;
public ViewModel()
{
instance = new instance
{ //your mock value for the properties..
FirstName = "Offer",
LastName = "Somthing"
};
}
public ViewModel(Model_A instance)
{
this.instance = instance;
}
}
And this is for your view, if you view in the ide designer you will have a mock view model to show.
public class View_For_ViewModelA1
{
public View_For_ViewModel_A1()
{
//this is the generated constructor already implemented by the ide, just add to it:
DataContext = new ViewModel_A1();
}
public View_For_ViewModel_A1(ViewModel_A1 vm)
{
DataContext = vm;
}
}
XAML Side:
<Window x:Class="WpfApplication1.View_For_ViewModel_A1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:ViewModel="clr-namespace:WpfApplication1"
mc:Ignorable="d" d:DesignHeight="300" d:DesignWidth="300"
d:DataContext="{d:DesignInstance ViewModel:ViewModel_A1, IsDesignTimeCreatable=True}"
Title="Window1" Height="300" Width="300">
<Grid>
<TextBox Text="{Binding FirstName}" />
<TextBox Text="{Binding LastName}" />
</Grid>
</Window>
In a more advanced scenario you would want to have a single view model class to relate to several model classes.. but you always should set a view to bind to a single view model. if you need to kung-fu with your code - make sure you do that in your view model layer. (i.e. creating a view-model that have several instances of different model types)
Note: This is not the complete pattern of mvvm.. in the complete pattern you can expose command which relate to methods in your model via your view-model and bind-able to your view as well. Good luck :)
Upvotes: 3
Reputation: 10013
I basically follow this pattern:
public class ViewModelWrappers
{
static MemberViewModel _memberViewModel;
public static MemberViewModel MemberViewModel
{
get
{
if (_memberViewModel == null)
_memberViewModel = new MemberViewModel(Application.Current.Resources["UserName"].ToString());
return _memberViewModel;
}
}
...
}
To bind this to a page is:
DataContext = ViewModelWrappers.MemberViewModel;
And if I'm using more than 1 ViewModel on the page I just bind to the wrapper.
DataContext = ViewModelWrappers;
Upvotes: 0