CODEWITHSUNDEEP
javascriptajaxxmlhttprequest
user123
user123

Reputation: 5407

Performing sequential ajax request

I tried to perfrom two sequential ajax request like:

var xmlhttp;
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("POST","data.php",true);
xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlhttp.send('url=' + url);
var x=10;
var y=20;
xmlhttp.open("POST","datatest.php",true);
xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlhttp.send('x=' + x, 'y=' + y);

Does not Give error, but says:

POST http://dev01.dev/data.php Aborted

And shows result of echo in datatest.php only. HOw can i get response from both data.php and datatest.php?

UPDATE:

data.php will give some result. 

echo $result1;

datatest.php will give some result. 

echo $result2;

I want to append above two result in myDiv.

If I do 

document.getElementById("myDiv").innerHTML=xmlhttp.responseText1;

then 

document.getElementById("myDiv").innerHTML=xmlhttp.responseText2;

It will replace the content. I want to append it!

Upvotes: 0

Views: 1076

Answers (1)

T.J. Crowder
T.J. Crowder

Reputation: 1074148

HOw can i get response from both data.php and datatest.php?

Use a separate XHR object rather than attempting to reuse the existing one. Your current code starts a request, but then you do xmlhttp.open("POST","datatest.php",true); on that same XHR object again before the request has time to finish, so it gets aborted.

For example:

var xmlhttp1, xmlhttp2;
function getXHR() {
    if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari
        return new XMLHttpRequest();
    }
    else { // code for IE6, IE5
        return new ActiveXObject("Microsoft.XMLHTTP");
    }
}
xmlhttp1 = getXHR();
xmlhttp1.onreadystatechange = function () {
    if (xmlhttp1.readyState == 4 && xmlhttp1.status == 200) {
        document.getElementById("myDiv").innerHTML = xmlhttp1.responseText;
    }
};
xmlhttp1.open("POST", "data.php", true);
xmlhttp1.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xmlhttp1.send('url=' + url);

var x = 10;
var y = 20;
xmlhttp2 = getXHR();
xmlhttp2.onreadystatechange = function () {
    // Presumably do someething with the result of this one, too
};
xmlhttp2.open("POST", "datatest.php", true);
xmlhttp2.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xmlhttp2.send('x=' + x, 'y=' + y);

Upvotes: 1

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