CODEWITHSUNDEEP
mysqlsqlleft-join
grabner
grabner

Reputation: 1239

Left join with multiple tables and conditions

I want to sort after a value in another table the current table is referenced to. My query looks like this:

SELECT o._id,
       o.titel,
       o.beschreibung
FROM   `objekt` AS o,
       `objekt_einzel` AS oe,
       `objekt_einzel_immobilie` AS oei,
       `objekt_art` AS oa,
       `verortung` AS v
       #here
       ,`person` AS p,
       `person_bauträger` AS pb
       #end
WHERE  o._id = oe.objekt_id
       AND oe._id = oei.objekt_einzel_id
       AND oa._id = o.objekt_art_id
       AND o.ort_id = v._id
       #here
       AND oe.bauträger_id = pb._id
       AND pb.person_id = p._id
       #end
       AND ( oei.justimmo_objekt_id = "0"
              OR oei.justimmo_objekt_id IS NULL
              OR oei.justimmo_objekt_id = "" )
#here
ORDER  BY p.firmenbezeichnung ASC

The query is working fine but it shows me only values if oe.bauträger_id is set. I also want the null values. So I need a left join. I tried different things but I only get messages like unknown column or I get too much results.

I tried to simplify it to this:

SELECT o._id,
       o.titel,
       o.beschreibung
FROM   `objekt` AS o,
       `objekt_einzel` AS oe,
        (SELECT oe.bauträger_id
        FROM objekt o, objekt_einzel oe, objekt_einzel_immobilie oei
        WHERE o._id = oe.objekt_id AND oe._id = oei.objekt_einzel_id) AS menge1
LEFT JOIN
        (SELECT pb._id AS bauträger_id
        FROM person p, person_bauträger pb
        WHERE p._id = pb.person_id) AS menge2
ON menge1.bauträger_id = menge2.bauträger_id
WHERE o._id = oe.objekt_id AND oe.bauträger_id = menge1.bauträger_id

but here I get a too big result set. I don't know how to explain this better. The data sets are too big to create an example. I hope you understand what I mean.

Upvotes: 0

Views: 266

Answers (1)

Palec
Palec

Reputation: 13551

SELECT o._id,
       o.titel,
       o.beschreibung
FROM   `objekt` AS o
       JOIN `objekt_einzel` AS oe ON o._id = oe.objekt_id
       JOIN `objekt_einzel_immobilie` AS oei ON oe._id = oei.objekt_einzel_id
       JOIN `objekt_art` AS oa ON o.objekt_art_id = oa._id
       JOIN `verortung` AS v ON o.ort_id = v._id
       LEFT JOIN `person_bauträger` AS pb ON oe.bauträger_id = pb._id
       LEFT JOIN `person` AS p ON pb.person_id = p._id
WHERE  oei.justimmo_objekt_id = "0"
       OR oei.justimmo_objekt_id IS NULL
       OR oei.justimmo_objekt_id = ""
ORDER  BY p.firmenbezeichnung ASC

This second try should work as it is just the original code rewritten using JOIN syntax and with LEFT JOINs.

Upvotes: 1

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