Reputation: 3141
I have the following two classes:
public class Person
{
public int Id { get; set; }
public string FullName { get; set; }
}
public class Trip
{
public int Id { get; set; }
public string Name { get; set; }
public virtual IEnumerable<Person> Persons { get; set; }
}
As you can see, a Trip can have 1 or more Persons...
I tried to use the EntityConfiguration to build the database properly but I cannot manage to make it work... I am quite confused on its usage:
public class TripConfiguration : EntityTypeConfiguration<Trip>
{
internal TripConfiguration()
{
// ???
}
}
What do I need to write to have the application to behave properly:
Upvotes: 0
Views: 47
Reputation: 2583
This is not a One-To-Many relationship, this is a Many-To-Many relationship, you need to have collections on both sides of the relationship. EF will create the joiner table on your behalf. Since today you cannot configure a person being in a trip only once you will need to create a unique constraint in your joiner table once is created to assure this happens since EF does not yet support Unique Key constraints through configuration.
public class Person
{
public int Id { get; set; }
public string FullName { get; set; }
public virtual ICollection<Trip> Trips { get; set; }
}
public class Trip
{
public int Id { get; set; }
public string Name { get; set; }
public virtual ICollection<Person> Persons { get; set; }
}
then
class PersonConfiguration : EntityTypeConfiguration<Person>
{
public PersonConfiguration()
{
this.HasMany(t => t.Trips).WithMany(t => t.Persons);
}
}
Upvotes: 0
Reputation: 4030
Try this:
this.HasRequired(x => x.Person)
.WithMany(x => x.Trips)
.HasForeignKey(x => x.PersonId);
Your classes:
public class Person
{
public int Id { get; set; }
public string FullName { get; set; }
public virtual ICollection<Trip> Trips { get; set;}
}
public class Trip
{
public int Id { get; set; }
public string Name { get; set; }
public int PersonId { get; set; }
public virtual Person Person { get; set; }
}
And as far that I know, EF doesn't support unique FK (or correct me if I'm wrong..). So you have to check it yourself.
Upvotes: 1