Reputation: 1787
I have a time as a number of milliseconds and I want to convert it to a HH:MM:SS
format. It should wrap around, with milliseconds = 86400000
I want to get 00:00:00
.
Upvotes: 145
Views: 291372
Reputation: 9
This converts milliseconds to 3 different human-readable values.
/**
* Converts milliseconds to 3 different human-readable values
* @param {{duration: number, includeSeconds: boolean, includeDays: boolean}} params
* @returns {[string, string, string, {days: (number | string), hours: (number | string), minutes: (number | string), seconds: (number | string), milliseconds: number}]} An array with 4 values, the first 3 being human
* readable values, the last being the value of each time duration.
*/
function msToTime({
duration,
includeSeconds = true,
includeDays = false
}) {
let milliseconds = Math.floor((duration % 1000) / 100),
seconds = Math.floor((duration / 1000) % 60),
minutes = Math.floor((duration / (1000 * 60)) % 60),
hours = Math.floor((duration / (1000 * 60 * 60)) % 24),
days = Math.floor(duration / (1000 * 60 * 60 * 24))
days = days < 10 ? '0' + days : days
hours = hours < 10 ? '0' + hours : hours
minutes = minutes < 10 ? '0' + minutes : minutes
seconds = seconds < 10 ? '0' + seconds : seconds
return [
// Returns padded time values, if days and seconds were set to be
// included, it'll appear in hierarchical order. E.g. "01:00:00:00.0",
// where '01' is the days value, and '00.0' is the seconds value.
`${includeDays ? `${days}:` : ''}${hours}:${minutes}${
includeSeconds ? `:${seconds}.${milliseconds}` : ''
}`,
// Returns trimmed time values, if days and seconds were set to be
// included, it'll appear in hierarchical order. E.g. "0:1:0:0", where
// the first '0' is the days value, and the last '0' is the seconds
// value.
`${includeDays ? `${Number(days)}:` : ''}${Number(hours)}:${Number(
minutes
)}${includeSeconds ? `:${Number(seconds)}` : ''}`,
// Returns human readable time in this format if days and seconds were
// set to be included: "8 days, 19 hours, 17 minutes, 10 seconds".
`${
includeDays && Number(days)
? `${Number(days)} day${
Number(days) > 1 || Number(days) === 0 ? 's' : ''
}${Number(hours) ? ', ' : ''}`
: ''
}${
Number(hours)
? `${Number(hours)} hour${
Number(hours) > 1 || Number(hours) === 0 ? 's' : ''
}${Number(minutes) ? ', ' : ''}`
: ''
}${
Number(minutes)
? `${Number(minutes)} minute${
Number(minutes) > 1 || Number(minutes) === 0 ? 's' : ''
}${includeSeconds && Number(seconds) ? ', ' : ''}`
: ''
}${
includeSeconds && Number(seconds)
? `${Number(seconds)} second${
Number(seconds) > 1 || Number(seconds) === 0 ? 's' : ''
}`
: ''
}` || 'a moment',
// Returns the padded values of each time unit.
{
days,
hours,
minutes,
seconds,
milliseconds
},
]
}
console.log(
msToTime({
duration: 86400000,
includeSeconds: true,
includeDays: true
})
)
console.log(
msToTime({
duration: 3600000,
includeSeconds: true,
includeDays: true
})
)
console.log(
msToTime({
duration: 760630000,
includeSeconds: true,
includeDays: true
})
)
console.log(
msToTime({
duration: 1000,
includeSeconds: true,
includeDays: true
})
)
console.log(
msToTime({
duration: 100,
includeSeconds: false,
includeDays: false
})
)
Upvotes: -1
Reputation: 11173
A Date object can be constructed from milliseconds:
const date = new Date(0, 0, 0, 0, 0, 0, milliseconds);
In your question you say milliseconds should 'wrap around' at 86400000. Since we know there are 86400000 milliseconds in a day, we can simply take the time from the date object, and ignore every other part of the date as irrelevant.
The time can then be obtained in any number of formats. The one you require matches that used in the United Kingdom, locale en-GB
:
const hms = d.toLocaleTimeString('en-GB');
Upvotes: 3
Reputation: 28556
Complete period pipe i'm using in Angular app. It convert days, too.
import { Pipe, PipeTransform, Injectable } from '@angular/core';
@Pipe({
name: 'period'
})
@Injectable({
providedIn: 'root'
})
export class PeriodPipe implements PipeTransform {
transform(value: any): any {
return this.intervalFormat(value);
}
private intervalFormat(ms:number) {
if(ms == 0 || typeof ms == 'undefined' || ms == null) {
return '0ms';
} else {
let ms1 = Math.abs(ms);
let dd = Math.floor(ms1/1000/3600/24);
if(dd > 0) {
ms1 = ms1%(dd*24*3600*1000);
}
let sec = ms1/1000;
let hh = Math.floor(sec/3600);
let mm = Math.floor((sec%3600)/60);
let ss = Math.floor((sec%3600)%60);
let ms2 = Math.floor(ms1%1000);
let ret = (dd!=0?(this.zeroPad(dd,1) + 'd '):'') +
(hh!=0?(this.zeroPad(hh,1) + 'h '):'') +
(mm!=0?(this.zeroPad(mm,2) + 'm '):'') +
(ss!=0?(this.zeroPad(ss,2) + 's '):'') +
(ms2!=0?(this.zeroPad(ms2,1) + 'ms '):'');
return ret;
}
}
private zeroPad(num:number, places:number) {
let zero = places - num.toString().length + 1;
return Array(+(zero > 0 && zero)).join("0") + num;
}
}
Upvotes: 0
Reputation: 20101
Based on the modulus approach of other answers, this is a modern, compact ES6 approach:
function splitMillis(millis){
const days = Math.floor(millis / 86400000);
const hours = Math.floor(millis / 3600000) % 24;
const minutes = Math.floor(millis / 60000) % 60;
const seconds = Math.floor(millis / 1000) % 60;
const millisRemaining = millis % 1000;
return { days, hours, minutes, seconds, millis : millisRemaining };
}
You can destructure the result to make your life easy.
const { days, hours, minutes, seconds, millis } = splitMillis(2824461)
You can also just destructure what you're interested in:
const { minutes, seconds } = splitMillis(2824461)
This answer is better than some of the answers here because it doesn't require a full Timestamp. For example, if you want to know elapsed time or time differential as in splitMillis(new Date() - someOtherDate)
All that being said, I hope this answer becomes obsolete soon with Temporal
: https://tc39.es/proposal-temporal/docs/cookbook.html
Upvotes: 2
Reputation: 9
Use UTCString...
let timeStr = new Date(millis).toUTCString().match("..:..:..")[0];
// timeStr = "20:30:22"
Upvotes: 0
Reputation: 1097
e.g. 21 Days, 14 Hrs, 18 Min, 18 Sec, 753 milliseconds.
Building off of @Nofi's awesome answer for human readable output, I made a more readable (in my opinion) and accurate version (and less complicated than @Steven Spungin's answer, albeit theirs is really cool) for my personal use and I figured I'd share it here.
function msToTime(ms) {
let seconds = Math.floor((ms / 1000) % 60);
let minutes = Math.floor((ms / (1000 * 60)) % 60);
let hours = Math.floor((ms / (1000 * 60 * 60)) % 24);
let days = Math.floor(ms / (1000 * 60 * 60 * 24));
let time = '';
if (days > 0) {
time += days + " Days, ";
ms -= days * (1000 * 60 * 60 * 24);
}
if (hours > 0) {
time += hours + " Hrs, ";
ms -= hours * (1000 * 60 * 60);
}
if (minutes > 0) {
time += minutes + " Min, ";
ms -= minutes * (1000 * 60);
}
if (seconds > 0) {
time += seconds + " Sec, ";
ms -= seconds * 1000;
}
return time += ms + " milliseconds.";
}
console.log('msToTime(1865898753): \n', msToTime(1865898753));
console.log('msToTime(123456789): \n', msToTime(123456789));
console.log('msToTime(85457): \n', msToTime(85457));
console.log('msToTime(547): \n', msToTime(547));
Upvotes: 1
Reputation: 1
If anyone still need here's a modified version of one of the code snippets posted above in js by https://stackoverflow.com/a/58826445/20067539
function timeConversion(duration) {
var portions = [];
var msInDay = 1000 * 60 * 60 * 24
var days = Math.trunc(duration / msInDay);
if (days > 0 ) {
portions.push(days + (days === 1 ? " day" : " days"))
duration = duration - (days * msInDay)
}
var msInHour = 1000 * 60 * 60;
var hours = Math.trunc(duration / msInHour);
if (hours > 0) {
portions.push(hours + (hours === 1 ? ' hour' : ' hours'));
duration = duration - (hours * msInHour);
}
var msInMinute = 1000 * 60;
var minutes = Math.trunc(duration / msInMinute);
if (minutes > 0) {
portions.push(minutes + (minutes === 1 ? ' minute' : ' minutes'));
duration = duration - (minutes * msInMinute);
}
var seconds = Math.trunc(duration / 1000);
if (seconds > 0) {
portions.push(seconds + (seconds === 1 ? ' second' : ' seconds'));
}
return portions.join(' ');
}
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000)));
console.log(timeConversion((60 * 60 * 1000)));
console.log(timeConversion((60 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((59 * 1000)));
Upvotes: -1
Reputation: 9488
I don't see the need for complication in all these answers, it's easy to add zeros by adding a power of 10:
function timeToString(t) {
const value =
((t / 3600_000 % 24) | 0) * 10000 +
((t / 60_000 % 60) | 0) * 100 +
((t / 1_000 % 60) | 0);
return (1000000 + value).toString().replace(/1(..)(..)(..)/, '$1:$2:$3');
}
Upvotes: -1
Reputation: 764
I recently ran into this situation. My focus was on clean readability and reusability.
(See function definition below)
timeUnits(86400000) // {days: 1, hours: 0, minutes: 0, seconds: 0, ms: 0}
Then you can use the data to do whatever you want (like build a string).
Other examples:
timeUnits(214870123) // {days: 2, hours: 11, minutes: 41, seconds: 10, ms: 123}
timeUnits('70123') // null
/**
* Converts milliseconds into greater time units as possible
* @param {int} ms - Amount of time measured in milliseconds
* @return {?Object} Reallocated time units. NULL on failure.
*/
function timeUnits( ms ) {
if ( !Number.isInteger(ms) ) {
return null
}
/**
* Takes as many whole units from the time pool (ms) as possible
* @param {int} msUnit - Size of a single unit in milliseconds
* @return {int} Number of units taken from the time pool
*/
const allocate = msUnit => {
const units = Math.trunc(ms / msUnit)
ms -= units * msUnit
return units
}
// Property order is important here.
// These arguments are the respective units in ms.
return {
// weeks: allocate(604800000), // Uncomment for weeks
days: allocate(86400000),
hours: allocate(3600000),
minutes: allocate(60000),
seconds: allocate(1000),
ms: ms // remainder
}
}
It's written in such a way so that you can easily implement other units (for example, where I commented out implementation for weeks) so long as you know their worth in milliseconds.
Upvotes: 7
Reputation: 406
let dateTimeStr = new Date(1949778000);
dateTimeStr = Math.floor(dateTimeStr/86400000) +' days '+ dateTimeStr.getHours() +' hours '+ dateTimeStr.getMinutes() +' minutes '+ dateTimeStr.getSeconds() +' seconds';
console.log(dateTimeStr);
You don't have to calculate the days if you don't need them
"22 days 16 hours 36 minutes 18 seconds"
Upvotes: 0
Reputation: 3306
A refactor from @dusht to ES6+ and more functional:
const addPrefix = time => time < 10 ? '0' + time : time;
const toHours = time => addPrefix(Math.floor((time / (1000 * 60 * 60)) % 24));
const toMinutes = time => addPrefix(Math.floor((time / (1000 * 60)) % 60));
const toSeconds = (ime => addPrefix(Math.floor((time / 1000) % 60));
const toMiliseconds = time => Math.floor((time % 1000) / 100);
const milisecondToHoursAndMinute = time => {
const hours = toHours(time);
const minutes = toMinutes(time);
const seconds = toSeconds(time);
const miliseconds = toMiliseconds(time);
return `${hours}:${minutes}:${seconds}.${miliseconds}`
}
Upvotes: 0
Reputation: 1277
hh:mm:ss
with optional padding(1:59:59
or 01:59:59
)
(1:59
or 01:59
)
(Default: no padding)
Based loosely on Chand's answer.
function formatMilliseconds(milliseconds, padStart) {
function pad(num) {
return `${num}`.padStart(2, '0');
}
let asSeconds = milliseconds / 1000;
let hours = undefined;
let minutes = Math.floor(asSeconds / 60);
let seconds = Math.floor(asSeconds % 60);
if (minutes > 59) {
hours = Math.floor(minutes / 60);
minutes %= 60;
}
return hours
? `${padStart ? pad(hours) : hours}:${pad(minutes)}:${pad(seconds)}`
: `${padStart ? pad(minutes) : minutes}:${pad(seconds)}`;
}
Tests:
let s = 1000;
let m = 60*s;
let h = 60*m;
console.log(formatMilliseconds(1*h)); // 1:00:00
console.log(formatMilliseconds(1*h, true)); // 01:00:00
console.log(formatMilliseconds(59*m + 59*s)); // 59:59
console.log(formatMilliseconds(59*m + 59*s, true)); // 59:59
console.log(formatMilliseconds(9*m + 9*s)); // 9:09
console.log(formatMilliseconds(9*m + 9*s, true)); // 09:09
console.log(formatMilliseconds(5*s)); // 0:05
console.log(formatMilliseconds(5*s, true)); // 00:05
console.log(formatMilliseconds(2400*s)); // 40:00
console.log(formatMilliseconds(2400*s, true)); // 40:00
.
.
.
If you need millisecond precision, you can get the fractional part using the following:
(asSeconds % 1).toFixed(3).substring(1)
Your returns would end up looking like this (break it up for readability as necessary):
`${padStart ? pad(hours) : hours}:${pad(minutes)}:${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`
There are probably better ways to do that, but this naive solution gets the job done.
Test:
let asSeconds = 59.5219;
let seconds = Math.floor(asSeconds);
console.log(`${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Equivalent to above, without using `pad()`:
//console.log(`${String(seconds).padStart(2, '0')}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Output: 59.522
Upvotes: 6
Reputation: 4960
How about creating a function like this:
function msToTime(duration) {
var milliseconds = Math.floor((duration % 1000) / 100),
seconds = Math.floor((duration / 1000) % 60),
minutes = Math.floor((duration / (1000 * 60)) % 60),
hours = Math.floor((duration / (1000 * 60 * 60)) % 24);
hours = (hours < 10) ? "0" + hours : hours;
minutes = (minutes < 10) ? "0" + minutes : minutes;
seconds = (seconds < 10) ? "0" + seconds : seconds;
return hours + ":" + minutes + ":" + seconds + "." + milliseconds;
}
console.log(msToTime(300000))
Upvotes: 209
Reputation: 2175
To Convert time in millisecond to human readable format.
function msToTime(ms) {
let seconds = (ms / 1000).toFixed(1);
let minutes = (ms / (1000 * 60)).toFixed(1);
let hours = (ms / (1000 * 60 * 60)).toFixed(1);
let days = (ms / (1000 * 60 * 60 * 24)).toFixed(1);
if (seconds < 60) return seconds + " Sec";
else if (minutes < 60) return minutes + " Min";
else if (hours < 24) return hours + " Hrs";
else return days + " Days"
}
console.log(msToTime(1000))
console.log(msToTime(10000))
console.log(msToTime(300000))
console.log(msToTime(3600000))
console.log(msToTime(86400000))
Upvotes: 92
Reputation: 1285
// The following is written in Typescript, should be easy to translate to JS
function humanReadableDuration(msDuration: int): string {
const h = Math.floor(msDuration / 1000 / 60 / 60);
const m = Math.floor((msDuration / 1000 / 60 / 60 - h) * 60);
const s = Math.floor(((msDuration / 1000 / 60 / 60 - h) * 60 - m) * 60);
// To get time format 00:00:00
const seconds: string = s < 10 ? `0${s}` : `${s}`;
const minutes: string = m < 10 ? `0${m}` : `${m}`;
const hours: string = h < 10 ? `0${h}` : `${h}`;
return `${hours}h ${minutes}m ${seconds}s`;
}
Upvotes: 4
Reputation: 1821
Extending on @Rick's answer, I prefer something like this:
function msToReadableTime(time){
const second = 1000;
const minute = second * 60;
const hour = minute * 60;
let hours = Math.floor(time / hour % 24);
let minutes = Math.floor(time / minute % 60);
let seconds = Math.floor(time / second % 60);
return hours + ':' + minutes + ":" + seconds;
}
Upvotes: 3
Reputation: 7
I works for me as i get milliseconds=1592380675409 using javascript method getTime() which returns the number of milliseconds between midnight of January 1, 1970 and the specified date.
var d = new Date();//Wed Jun 17 2020 13:27:55 GMT+0530 (India Standard Time)
var n = d.getTime();//1592380675409 this value is store somewhere
//function call
console.log(convertMillisecToHrMinSec(1592380675409));
var convertMillisecToHrMinSec = (time) => {
let date = new Date(time);
let hr = date.getHours();
let min = date.getMinutes();
let sec = date.getSeconds();
hr = (hr < 10) ? "0"+ hr : hr;
min = (min < 10) ? "0"+ min : min;
sec = (sec < 10) ? "0"+ sec : sec;
return hr + ':' + min + ":" + sec;//01:27:55
}
Upvotes: 0
Reputation: 1449
Human-readable code for human-readable output and you can extend this to light years or nanoseconds or what have you very intuitively. Obviously you'd want to convert this to a function and re-use some of those intermediate modulo calls.
second = 1000
minute = second * 60
hour = minute * 60
day = hour * 24
test = 3 * day + 2 * hour + 11 * minute + 58 * second
console.log(Math.floor(test / day))
console.log(Math.floor(test % day / hour))
console.log(Math.floor(test % day % hour / minute))
console.log(Math.floor(test % day % hour % minute / second))
Upvotes: 3
Reputation: 207
Sorry, late to the party. The accepted answer did not cut it for me, so I wrote it myself.
Output:
2h 59s
1h 59m
1h
1h 59s
59m 59s
59s
Code (Typescript):
function timeConversion(duration: number) {
const portions: string[] = [];
const msInHour = 1000 * 60 * 60;
const hours = Math.trunc(duration / msInHour);
if (hours > 0) {
portions.push(hours + 'h');
duration = duration - (hours * msInHour);
}
const msInMinute = 1000 * 60;
const minutes = Math.trunc(duration / msInMinute);
if (minutes > 0) {
portions.push(minutes + 'm');
duration = duration - (minutes * msInMinute);
}
const seconds = Math.trunc(duration / 1000);
if (seconds > 0) {
portions.push(seconds + 's');
}
return portions.join(' ');
}
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) ));
console.log(timeConversion((60 * 60 * 1000) ));
console.log(timeConversion((60 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion( (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion( (59 * 1000)));
Upvotes: 16
Reputation: 399
Here is my solution
let h,m,s;
h = Math.floor(timeInMiliseconds/1000/60/60);
m = Math.floor((timeInMiliseconds/1000/60/60 - h)*60);
s = Math.floor(((timeInMiliseconds/1000/60/60 - h)*60 - m)*60);
// to get time format 00:00:00
s < 10 ? s = `0${s}`: s = `${s}`
m < 10 ? m = `0${m}`: m = `${m}`
h < 10 ? h = `0${h}`: h = `${h}`
console.log(`${s}:${m}:${h}`);
Upvotes: 26
Reputation: 330
Worked for me
msToTime(milliseconds) {
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h == "00" ? m + ':' + s : h + ':' + m + ':' + s;
}
Upvotes: 3
Reputation: 792
In my implementation I used Moment.js:
export default (value) =>
const duration = moment.duration(value);
const milliseconds = duration.milliseconds();
const seconds = duration.seconds();
const minutes = duration.minutes();
const hours = duration.hours();
const day = duration.days();
const sDay = `${day}d `;
const sHours = (hours < 10) ? `0${hours}h ` : `${hours}h `;
const sMinutes = (minutes < 10) ? `0${minutes}' ` : `${minutes}' `;
const sSeconds = (seconds < 10) ? `0${seconds}" ` : `${seconds}" `;
const sMilliseconds = `${milliseconds}ms`;
...
}
Once got the strings, I composed them as I want.
Upvotes: 0
Reputation: 1
If you're using typescript, this could be a good thing for you
enum ETime {
Seconds = 1000,
Minutes = 60000,
Hours = 3600000,
SecInMin = 60,
MinInHours = 60,
HoursMod = 24,
timeMin = 10,
}
interface ITime {
millis: number
modulo: number
}
const Times = {
seconds: {
millis: ETime.Seconds,
modulo: ETime.SecInMin,
},
minutes: {
millis: ETime.Minutes,
modulo: ETime.MinInHours,
},
hours: {
millis: ETime.Hours,
modulo: ETime.HoursMod,
},
}
const dots: string = ":"
const msToTime = (duration: number, needHours: boolean = true): string => {
const getCorrectTime = (divider: ITime): string => {
const timeStr: number = Math.floor(
(duration / divider.millis) % divider.modulo,
)
return timeStr < ETime.timeMin ? "0" + timeStr : String(timeStr)
}
return (
(needHours ? getCorrectTime(Times.hours) + dots : "") +
getCorrectTime(Times.minutes) +
dots +
getCorrectTime(Times.seconds)
)
}
Upvotes: 0
Reputation: 29109
This solution uses one function
to split milliseconds into a parts object
, and another function
to format the parts object
.
I created 2 format functions, one as you requested, and another that prints a friendly string and considering singular/plural, and includes an option to show milliseconds.
function parseDuration(duration) {
let remain = duration
let days = Math.floor(remain / (1000 * 60 * 60 * 24))
remain = remain % (1000 * 60 * 60 * 24)
let hours = Math.floor(remain / (1000 * 60 * 60))
remain = remain % (1000 * 60 * 60)
let minutes = Math.floor(remain / (1000 * 60))
remain = remain % (1000 * 60)
let seconds = Math.floor(remain / (1000))
remain = remain % (1000)
let milliseconds = remain
return {
days,
hours,
minutes,
seconds,
milliseconds
};
}
function formatTime(o, useMilli = false) {
let parts = []
if (o.days) {
let ret = o.days + ' day'
if (o.days !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.hours) {
let ret = o.hours + ' hour'
if (o.hours !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.minutes) {
let ret = o.minutes + ' minute'
if (o.minutes !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.seconds) {
let ret = o.seconds + ' second'
if (o.seconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (useMilli && o.milliseconds) {
let ret = o.milliseconds + ' millisecond'
if (o.milliseconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (parts.length === 0) {
return 'instantly'
} else {
return parts.join(' ')
}
}
function formatTimeHMS(o) {
let hours = o.hours.toString()
if (hours.length === 1) hours = '0' + hours
let minutes = o.minutes.toString()
if (minutes.length === 1) minutes = '0' + minutes
let seconds = o.seconds.toString()
if (seconds.length === 1) seconds = '0' + seconds
return hours + ":" + minutes + ":" + seconds
}
function formatDurationHMS(duration) {
let time = parseDuration(duration)
return formatTimeHMS(time)
}
function formatDuration(duration, useMilli = false) {
let time = parseDuration(duration)
return formatTime(time, useMilli)
}
console.log(formatDurationHMS(57742343234))
console.log(formatDuration(57742343234))
console.log(formatDuration(5423401000))
console.log(formatDuration(500))
console.log(formatDuration(500, true))
console.log(formatDuration(1000 * 30))
console.log(formatDuration(1000 * 60 * 30))
console.log(formatDuration(1000 * 60 * 60 * 12))
console.log(formatDuration(1000 * 60 * 60 * 1))
Upvotes: 5
Reputation: 2820
I needed time only up to one day, 24h, this was my take:
const milliseconds = 5680000;
const hours = `0${new Date(milliseconds).getHours() - 1}`.slice(-2);
const minutes = `0${new Date(milliseconds).getMinutes()}`.slice(-2);
const seconds = `0${new Date(milliseconds).getSeconds()}`.slice(-2);
const time = `${hours}:${minutes}:${seconds}`
console.log(time);
you could get days this way as well if needed.
Upvotes: 6
Reputation: 1234
The above snippets don't work for cases with more than 1 day (They are simply ignored).
For this you can use:
function convertMS(ms) {
var d, h, m, s;
s = Math.floor(ms / 1000);
m = Math.floor(s / 60);
s = s % 60;
h = Math.floor(m / 60);
m = m % 60;
d = Math.floor(h / 24);
h = h % 24;
h += d * 24;
return h + ':' + m + ':' + s;
}
Thanks to https://gist.github.com/remino/1563878
Upvotes: 8
Reputation: 729
Based on @Chand answer. This is the implementation in Typescript. A bit safer than coercing types in JS. If you remove the type annotation should be valid JS. Also using new string functions to normalise the time.
function displayTime(millisec: number) {
const normalizeTime = (time: string): string => (time.length === 1) ? time.padStart(2, '0') : time;
let seconds: string = (millisec / 1000).toFixed(0);
let minutes: string = Math.floor(parseInt(seconds) / 60).toString();
let hours: string = '';
if (parseInt(minutes) > 59) {
hours = normalizeTime(Math.floor(parseInt(minutes) / 60).toString());
minutes = normalizeTime((parseInt(minutes) - (parseInt(hours) * 60)).toString());
}
seconds = normalizeTime(Math.floor(parseInt(seconds) % 60).toString());
if (hours !== '') {
return `${hours}:${minutes}:${seconds}`;
}
return `${minutes}:${seconds}`;
}
Upvotes: 2
Reputation: 10232
my solution
var sunriseMills = 1517573074000; // sunrise in NewYork on Feb 3, 2018 - UTC time
var offsetCityMills = -5 * 3600 * 1000; // NewYork delay to UTC
var offsetDeviceMills = new Date().getTimezoneOffset() * 60 * 1000 ; // eg. I live in Romania (UTC+2) >> getTimezoneOffset() = 120
var textTime = new Date(sunriseMills + offsetCityMills + offsetDeviceMills)
.toLocaleTimeString('en-US', { hour: 'numeric', minute: 'numeric' });
textTime will become '7.04 AM'
Upvotes: 1
Reputation: 579
This one returns time like youtube videos
function getYoutubeLikeToDisplay(millisec) {
var seconds = (millisec / 1000).toFixed(0);
var minutes = Math.floor(seconds / 60);
var hours = "";
if (minutes > 59) {
hours = Math.floor(minutes / 60);
hours = (hours >= 10) ? hours : "0" + hours;
minutes = minutes - (hours * 60);
minutes = (minutes >= 10) ? minutes : "0" + minutes;
}
seconds = Math.floor(seconds % 60);
seconds = (seconds >= 10) ? seconds : "0" + seconds;
if (hours != "") {
return hours + ":" + minutes + ":" + seconds;
}
return minutes + ":" + seconds;
}
Output:
Upvotes: 22
Reputation: 1271
I had the same problem, this is what I ended up doing:
function parseMillisecondsIntoReadableTime(milliseconds){
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h + ':' + m + ':' + s;
}
var time = parseMillisecondsIntoReadableTime(86400000);
alert(time);
Upvotes: 38