CODEWITHSUNDEEP
javascriptarraysfor-loopwhile-loop
Zackary Lundquist
Zackary Lundquist

Reputation: 101

Return all possible sums of number array

I have gone over my code a million times and can't figure out the problem. I have made a code that will return all the possible sums of numbers within an array. It works fine when there are 3 numbers in the array but if I add another number to the array it replaces a few of what should be sums with NaN. Ex:

array = [4, 6, 3, 7] is returning:

[ 20, 16, 10, 13, 9, 14, 11, 7, 17, NaN, 13 ] and NaN should be "10"

array = [4, 6, 3, 7];
newarray = [0];
for (i = 0; i < array.length; i++) {
    newarray[0] += array[i];
}
x = 0;
y = 1;
for (i = 0; i < array.length; i++) {
    newarray.push((newarray[0]-array[i])); 
    if (i !== 0) {
        y = y+array.length; 
    }
    x = i;
    while (x < array.length) {
        if (x != i) {
            newarray.push((newarray[y]-array[x]));
        }
        x++;
    }
}
console.log(newarray);`

The fact that I am getting NaN in some slots where numbers should be leads me to believe there is a problem with variable x in the while loop but my brain is being racked on where the issue actually is. http://jsfiddle.net/nsjY6/

Upvotes: 0

Views: 625

Answers (1)

farmer1992
farmer1992

Reputation: 8156

newarray[y] here cause NaN

newarray.push((newarray[y - 1]-array[x]));

[ 20, 16, 14, 17, 13, 14, 10, 6, 17, 10, 13 ]

add my version

var array = [4, 6, 3, 7];

var newarray = [];

for (i=0; i< Math.pow(2, array.length); i++) {

    var s = i.toString(2)
    var t = 0;
    for (c in s) t += s[c] * array[c];

    newarray.push(t);
}

console.log(newarray);

Upvotes: 2

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