Jujo
Jujo

Reputation: 79

Extract specific values or substrings from long string using regex in java

I have a long string containing different values/strings i want to extract.

String info = "ABHom=1.00;AC=2;AF=1.00;AN=2;DP=24;Dels=0.00;FS=0.000;
              HaplotypeScore=0.9947;MLEAC=2;MLEAF=1.00;MQ=53.03;MQ0=0;QD=32.49;
              VQSLOD=2.70; culprit=FS";



Matcher matcher = Pattern.compile("[A][B][h][o][m][=]([0-9]+\\.[0-9]+)").matcher(info);
if (matcher.find()) {
    String someNumberStr = matcher.group(1);
        ABhom = Double.parseDouble(someNumberStr);

Matcher matcher = Pattern.compile("[M][L][E][A][C][=]/([0-9]+)").matcher(info);
if (matcher.find()) {
    String someNumberStr = matcher.group(1);
        MLEAC = Integer.parseInt(someNumberStr);

I'am new to regex. Is there any smarter way to extract the numbers/strings after the equals sign ?

I'am thankful for any suggestions!

Upvotes: 2

Views: 7511

Answers (5)

Simon
Simon

Reputation: 113

I don't think regex is a good idea. Try info.split(";")[0].split("=")[1] with some extra boundary check.

Upvotes: 0

Melih Altıntaş
Melih Altıntaş

Reputation: 2535

    String info = "ABHom=1.00;AC=2;AF=1.00;AN=2;DP=24;Dels=0.00;FS=0.000;"
            + " HaplotypeScore=0.9947;MLEAC=2;MLEAF=1.00;MQ=53.03;MQ0=0;QD=32.49;"
            + "VQSLOD=2.70; culprit=FS";

    Pattern pattern = Pattern.compile("(\\w+)=(\\d+(.\\d+)?)");
    Matcher matcher = pattern.matcher(info);
    while (matcher.find()) {            
        System.out.println("key: "+matcher.group(1) +" value: "+matcher.group(2));
    }

output :

key: ABHom value: 1.00
key: AC value: 2
key: AF value: 1.00
key: AN value: 2
key: DP value: 24
key: Dels value: 0.00
key: FS value: 0.000
key: HaplotypeScore value: 0.9947
key: MLEAC value: 2
key: MLEAF value: 1.00
key: MQ value: 53.03
key: MQ0 value: 0
key: QD value: 32.49
key: VQSLOD value: 2.70

explanation :

\\w mean any character include _ \\w+ means array of characters
\\d mean any digit \\d+ means array of digits
? Matches the preceding element zero or one time. For example, ab?c matches only "ac" or "abc".

you said that i want to extract string and numbers , because of this the code above can not extract culprit=FS but if you want to extract all pair you should use this code :

    Pattern pattern = Pattern.compile("(\\w+)=([^;]+)");
    Matcher matcher = pattern.matcher(info);
    while (matcher.find()) {            
        System.out.println("key: "+matcher.group(1) +" value: "+matcher.group(2));
    }

output :

key: ABHom value: 1.00
key: AC value: 2
key: AF value: 1.00
key: AN value: 2
key: DP value: 24
key: Dels value: 0.00
key: FS value: 0.000
key: HaplotypeScore value: 0.9947
key: MLEAC value: 2
key: MLEAF value: 1.00
key: MQ value: 53.03
key: MQ0 value: 0
key: QD value: 32.49
key: VQSLOD value: 2.70
key: culprit value: FS

Upvotes: 0

dg_no_9
dg_no_9

Reputation: 1013

You can store them in HashMap as follows:

String[] parts = info.split(";");
Map<String, String> hashMap = new HashMap<String, String>();
for (String s : parts) {
       String[] keyVal = s.trim().split("=");
       hashMap.put(keyVal[0], keyVal[1]);
}

and later on you may use hashMap object to get it's values.

Upvotes: 0

Prabhakaran Ramaswamy
Prabhakaran Ramaswamy

Reputation: 26094

You can do like this

String[] split = info.split(";");
for (String string : split) {
       String[] split2 = string.trim().split("=");
       System.out.println(split2[0] +" :" +split2[1]);
}

Upvotes: 0

Dawood ibn Kareem
Dawood ibn Kareem

Reputation: 79838

I think what you want to do is to turn your String into a HashMap<String,String>.

First, you'll need to split your string around semicolons. Then, iterate the array that you get, splitting each entry around the equals sign, and adding the result to the HashMap.

I suggest you read about the split method of the String class for how to do this, and also read about the HashMap class. Look at http://docs.oracle.com/javase/7/docs/api/java/lang/String.html and http://docs.oracle.com/javase/7/docs/api/java/util/HashMap.html and post again if you need more help.

Upvotes: 5

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