Reputation: 3832
I am new to prolog and am considering using it for a small data analysis application. Here is what I am seeking to accomplish:
I have a CSV file with some data of the following from:
a,b,c
d,e,f
g,h,i
...
The data is purely numerical and I need to do the following: 1st, I need to group rows according to the following scheme:
So what's going on above?
I start at the 1st row, which has value 'a' in column one. Then, I keep going down the rows until I hit a row whose value in column one differs from 'a' by a certain amount, 'z'. The process is then repeated, and many "groups" are formed after the process is complete.
For each of these groups, I want to find the mean of columns two and three (as an example, for the 1st group in the picture above, the mean of column two would be: (b+e+h)/3).
I am pretty sure this can be done in prolog. However, I have 50,000+ rows of data and since prolog is declarative, I am not sure how efficient prolog would be at accomplishing the above task?
Is it feasible to work out a prolog program to accomplish the above task, so that efficiency of the program is not significantly lower than a procedural analog?
Upvotes: 1
Views: 242
Reputation: 60014
this snippet could be a starting point for your task
:- [library(dcg/basics)].
rownum(Z, AveList) :- phrase_from_file(row_scan(Z, [], [], AveList), 'numbers.txt').
row_scan(Z, Group, AveSoFar, AveList) -->
number(A),",",number(B),",",number(C),"\n",
{ row_match(Z, A,B,C, Group,AveSoFar, Group1,AveUpdated) },
row_scan(Z, Group1, AveUpdated, AveList).
row_scan(_Z, _Group, AveList, AveList) --> "\n";[].
% row_match(Z, A,B,C, Group,Ave, Group1,Ave1)
row_match(_, A,B,C, [],Ave, [(A,B,C)],Ave).
row_match(Z, A,B,C, [H|T],Ave, Group1,Ave1) :-
H = (F,_,_),
( A - F =:= Z
-> aggregate_all(agg(count,sum(C2),sum(C3)),
member((_,C2,C3), [(A,B,C), H|T]), agg(Count,T2,T3)),
A2 is T2/Count, A3 is T3/Count,
Group1 = [], Ave1 = [(A2,A3)|Ave]
; Group1 = [H,(A,B,C)|T], Ave1 = Ave
).
with this input
1,2,3
4,5,6
7,8,9
10,2,3
40,5,6
70,8,9
16,0,0
yields
?- rownum(6,L).
L = [ (3.75, 4.5), (5, 6)]
Upvotes: 1