CODEWITHSUNDEEP
javastringvariablescolors
Chronicle
Chronicle

Reputation: 1645

Use a variable like this: set.color(Color.variable)

In this method I make a string variable, and move it to a different one.

    private void produceRainbow() {
       String color = "RED";
       produceArc(color);
    }

There is more code there but it does not matter (essentially, changing the string to other colors).

Next this method:

private void produceArc(String color) {
    GOval arc = new GOval(leftX, upperY, rightX, lowerY); 
    arc.setColor(Color.color);
}

(Ignore the variables leftX, upperY, rightX, lowerY)

Here I want to set the color to a string. So I want it to become arc.setColor(Color.RED)

When I compile, I get this error:

Program.java:89: cannot find symbol
symbol  : variable color
location: class java.awt.Color
    arc.setColor(Color.color);

Is it even possible to do what I want to do? If so, what am I doing wrong?

(If you're curious, I made a seperate method for each arc (red, blue, green, etc, all have their own method) and this works, but I was wondering if I could just use one method that takes a variable, which makes the code a lot shorter)

Upvotes: 0

Views: 30399

Answers (1)

James
James

Reputation: 1036

To elaborate the comment I gave.

You could either pass the Color.RED right away or use Color.FromName(string name);

Suggested method:

To pass the Color.RED your methods will look like this: 

private void produceRainbow() {
       Color color = Color.RED;
       produceArc(color);
    }

And:

private void produceArc(Color color) {
    GOval arc = new GOval(leftX, upperY, rightX, lowerY); 
    arc.setColor(color);
}

Method 2

If, for some reason, you would use the FromName method you'd apply it like below:

private void produceRainbow() {
       String color = "Red";
       produceArc(color);
    }

And:

private void produceArc(String color) {
    GOval arc = new GOval(leftX, upperY, rightX, lowerY); 
    arc.setColor(Color.FromName(color));
}

Note that this last method is only working in C# and is not suitable for Java. (I'm not sure whether you're using Java or C#)

Upvotes: 1

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