Reputation: 3933
I can perform
a = [1,2,3]
b = [4,5,6]
a.extend(b)
# a is now [1,2,3,4,5,6]
Is there way to perform an action for extending list and adding new items to the beginning of the list?
Like this
a = [1,2,3]
b = [4,5,6]
a.someaction(b)
# a is now [4,5,6,1,2,3]
I use version 2.7.5, if it is important.
Upvotes: 43
Views: 36670
Reputation: 1122392
You can assign to a slice:
a[:0] = b
Demo:
>>> a = [1,2,3]
>>> b = [4,5,6]
>>> a[:0] = b
>>> a
[4, 5, 6, 1, 2, 3]
Essentially, list.extend()
is an assignment to the list[len(list):]
slice.
You can 'insert' another list at any position, just address the empty slice at that location:
>>> a = [1,2,3]
>>> b = [4,5,6]
>>> a[1:1] = b
>>> a
[1, 4, 5, 6, 2, 3]
Upvotes: 109
Reputation: 7177
If you need fast operations and you need to be able to access arbitrary elements, try a treap or red-black tree.
>>> import treap as treap_mod
>>> treap = treap_mod.treap()
>>> for i in range(100000):
... treap[i] = i
...
>>> treap[treap.find_min() - 1] = -1
>>> treap[100]
100
Most operations on treaps and red-black trees can be done in O(log(n)). Treaps are purportedly faster on average, but red-black trees give a lower variance in operation times.
Upvotes: 3
Reputation: 59984
You could use collections.deque
:
import collections
a = collections.deque([1, 2, 3])
b = [4, 5, 6]
a.extendleft(b[::-1])
Upvotes: 4