CODEWITHSUNDEEP
c++loopscout
Tayeb Ghagha
Tayeb Ghagha

Reputation: 5

how can I work with the last element of iterations

for(int t(0); t < 10;++t) { cout<<t<<endl;}

I'm just biginer in C++, and want to know how can I take the last elemnt of my "cout...."; in this case my laste element is 9

thx for help ;)

Upvotes: 0

Views: 149

Answers (6)

diapir
diapir

Reputation: 3040

You can extract int t from the for loop :

int t;  
for (t = 0; t < 10; ++t)  
{
    cout << t << endl;
}

Upvotes: 1

Vlad from Moscow
Vlad from Moscow

Reputation: 310990

It is not clear what you want but in any case your loop contains a bug. Instead of

for(int t(0); t < 10;  t) { cout<<t<<endl;}

should be

for(int t(0); t < 10;  t++) { cout<<t<<endl;}

that is variable t has to be incremented.

Upvotes: 0

Treader
Treader

Reputation: 11

int c = 0;
for(int t = 0; t<10; t++)
{
  c = t;
}
cout<<c;

This might be what you are looking for I am not sure I understand your question properly though.The variable c should hold the last element of t when the loop ends.

Upvotes: 1

user1708860
user1708860

Reputation: 1753

One simple way - 

int t = 0;
for (; t < 10; ++t)
   cout << t << ;

Tough the correct way to do it will be (one variable should not have two meanings, i.e 1. last element, 2. iterator context) - 

int last_element;
for (int t = 0; t < 10; ++t;
{
    cout << t << ;
    last_element = t;
}

Upvotes: -1

GMasucci
GMasucci

Reputation: 2892

ghagha, in C++ the ranges are run from 0 to n-1, in your example you have a range of 0 to < 10 hence 0 to 9, therefore your last element is 9. But as I said you can do any range as n-1 for the last element, provided that it follows normal conventions (it is possible to have a range from 1 to n if you code it that way)

Upvotes: 0

abelenky
abelenky

Reputation: 64682

int t = 9;
cout << t << endl;

Now you have the last element, #9.

Upvotes: 0

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