CODEWITHSUNDEEP
javaregex
Afrosimon
Afrosimon

Reputation: 285

Java Regular Expression

I need to remove some characters at the end of a certain list of item. These characters are always the same (C, CD, PDF, CPDF, M) and with this regular expression I'm able to get rid of them : 

str.replaceAll("(C|CD|PDF|CPDF|M)$", "");

However, I'm not able to inverse this expression : I'd like to be able to isolate (by removing the rest of the string, for exemple) any of these code, if they're at the end of the string. I tried this :

str.replaceAll("!(C|CD|PDF|CPDF|M)$", "");

I probably get by using some string functions, but I'm sure it's possible using only regular expression.

Upvotes: 1

Views: 342

Answers (4)

chburd
chburd

Reputation: 4159

Same as Josh Hight, except for the regexp that allow to get both parts

 Matcher m = Pattern.compile("(.*)(C|CD|PDF|CPDF|M)$").matcher("165N1JCD");
    while (m.find()) {
        System.out.println(m.group(1)); // prints out "165N1J"
        System.out.println(m.group(2)); // prints out "CD"
    }

Upvotes: 2

Alex Spurling
Alex Spurling

Reputation: 55864

If you don't want to use the Matcher class, you can stick with replaceAll:

str.replaceAll(".*(C|CD|PDF|CPDF|M)$", "$1");

Upvotes: 0

unholysampler
unholysampler

Reputation: 17321

You can use the Matcher class to grab a specific group (the suffix you remove) and perform the replaceAll operation. Another option would be to make your expression have two groups, the one you have and one before it for everything else.

Upvotes: 0

user240302
user240302

Reputation:

You're already using parenthesis to capture the matching group, now simply reference that group.

    Matcher m = Pattern.compile("(C|CD|PDF|CPDF|M)$").matcher("165N1JCD");
    while (m.find()) {
        System.out.println(m.group(1)); // prints out "CD"
    }

Upvotes: 5

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