CODEWITHSUNDEEP
c
user2948078
user2948078

Reputation:

Why in the next code c = 1?

Why in the next code c = 1 ?

#include <stdio.h>

int main()
{
    int i = 65537;
    char c = (char)i;
    printf("c = %d\n",c); /* why c =1 */
    return(0);
}

Upvotes: 6

Views: 351

Answers (4)

m0skit0
m0skit0

Reputation: 25874

65537 is 0x10001 (in hexadecimal, 10000000000000001 in binary). If you cast this value to char, which is only one byte long, you will only be taking the lowest (least-significant) byte from 0x1001, which is 0x01 = 1 in decimal.

Upvotes: 7

iDebD_gh
iDebD_gh

Reputation: 372

This for casting from int to char: int i = 65537; char c = (char)i;

First four bytes are casted here from 10000000000000001: this is why it coming as 1 if you use 65539 (10000000000000011), char will be 3

Upvotes: 0

cd611
cd611

Reputation: 141

The char type is only 8 bits long, while int has 32 bits. When you assign an int variable to a char, the value is cut to just the 8 least significant bits.

65537 is in binary 10000000 000000001

So, the least significant byte is 00000001

Upvotes: 4

StuartLC
StuartLC

Reputation: 107337

Char stores only 1 byte. By assigning c to an int value, only the lowest byte is assigned.

65537 = 256 * 256 + 1.

Hence c = 1.

Upvotes: 4

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