CODEWITHSUNDEEP
javaregexvalidationjsf
user1924104
user1924104

Reputation: 901

Custom validator for a phone number in JSF

i am trying to do some validation on a phone number although i understand how to do validation for just numbers of a set size this task is a little tricky

i am required to have validation on a users phone number however it must be in any one of the formats illustrated below (where spaces are not significant):

+44 (23) 92846438
(023) 92846438

how would i create a custom validation that would validate against all combinations of the above phone numbers ?

Thanks

i have tried created a backing bean and validating through that

public class PhoneValidator implements Validator{

private static final String phone_PATTERN = "^[0-9-]{12,15}$";

    private Pattern pattern;
    private Matcher matcher;

    public UserNameValidator(){
          pattern = Pattern.compile(phone_PATTERN);
    }

    @Override
    public void validate(FacesContext context, UIComponent component,
            Object value) throws ValidatorException {

        matcher = pattern.matcher(value.toString());
        if(!matcher.matches()){

            FacesMessage msg = 
                new FacesMessage("Phone validation failed", 
                        "Invalid phone number.");
            msg.setSeverity(FacesMessage.SEVERITY_ERROR);
            throw new ValidatorException(msg);

        }

    }
}

would something like this work :

private static final String phone_PATTERN = "^[+][44][(0-9)][0-9-]{12,15}$";

and if so how can i get it to check both methods

edit, i have tried the above but it does not work, i think i am on the right lines here just can not get the combination right

Upvotes: 0

Views: 5042

Answers (2)

Josh T
Josh T

Reputation: 564

^(\\+\\d\\d )?\\(\\d{2,3}\\) \\d{8}$

The above matches both of those examples. Test out regex real quick and easy @ regexpal.com

  • ^ matches the start of a string
  • $ matches the end of a string
  • \ java requires a double escape (for \d, ( etc.)
  • \d matches any single number (0-9)

  • {X} means the preceding pattern chunk must occur X times, {X,Y} also works if you're flexible

  • also consider using "|" (pipe character) which stands for "or". Ex: in X|Y It will grab matches of X or Y.

Upvotes: 1

user1924104
user1924104

Reputation: 901

managed to find the regular expression needed

incase anyone needs it it is here, it will work on any u.k. number

private static final String Phone_PATTERN = "^\\(?(?:(?:0(?:0|11)\\)?[\\s-]?\\(?|\\+)44\\)?[\\s-]?\\(?(?:0\\)?[\\s-]?\\(?)?|0)(?:\\d{2}\\)?[\\s-]?\\d{4}[\\s-]?\\d{4}|\\d{3}\\)?[\\s-]?\\d{3}[\\s-]?\\d{3,4}|\\d{4}\\)?[\\s-]?(?:\\d{5}|\\d{3}[\\s-]?\\d{3})|\\d{5}\\)?[\\s-]?\\d{4,5}|8(?:00[\\s-]?11[\\s-]?11|45[\\s-]?46[\\s-]?4\\d))(?:(?:[\\s-]?(?:x|ext\\.?\\s?|\\#)\\d+)?)$";

Upvotes: 0

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