Reputation: 29
I have set an Ajax call for Pagination. I need to pass one more vaiable which is stored in the URL
URL
http://thisite.com/pagetitl/?id=12 **// where 'id=' is a variable I want to pass.**
Ajax Call
function page(page) {
var dataString = '&page=' + page; // pagination with ajax
pag.ajax({
type: "GET",
url: "cmn_pg.php",
data: dataString,
success: function (ccc) {
pag("#search_results").html(ccc);
}
});
}
I have tried to GET it in PHP file $id=$_GET[id]
, but wont work.
I ask how to pass it with AJAX because I'm quite new to AJAX.
Upvotes: 0
Views: 16469
Reputation: 733
function page(page) {
var dataString = '&page=' + page; // pagination with ajax pag.ajax
({
type: "GET",
url: "cmn_pg.php",
data: {
page: page
},
success: function(ccc) {
pag("#search_results").html(ccc);
}
});
if more data is there to pass add to data variable as given bellow :-
data : {page:page,data2:data2},
Upvotes: 0
Reputation: 40639
Try this,
pag.ajax({
type: "GET",
url: "cmn_pg.php",
data: {
page: page, // your page number
id:12// your id to send
},
success: function (ccc) {
pag("#search_results").html(ccc);
}
});
Upvotes: 0
Reputation: 944443
If you are building your query string manually then:
dataString = 'page=' + encodeURIComponent(page);
but you are using jQuery, so don't build it manually:
url: "cmn_pg.php",
data: {
"page": page
},
success: function (ccc) {
(You also need to use the right name for it in PHP: <?php $id = $_GET['page'] ?>
)
Upvotes: 7
Reputation: 14883
You named the variable "page" and try to access it via "id" in PHP. You have to create the query string liek this:
var dataString = '&id=' + page;
Alertnitavly you can use pass an object to the "data" parameter andjQUery does the transformationf for you. Sample:
data: { id: page },
Data to be sent to the server. It is converted to a query string, if not already a string. It's appended to the url for GET-requests. See processData option to prevent this automatic processing. Object must be Key/Value pairs. If value is an Array, jQuery serializes multiple values with same key based on the value of the traditional setting (described below).
Soruce: http://api.jquery.com/jQuery.ajax/
Upvotes: 0
Reputation: 11984
You can pass via url like this
pag.ajax
({
type: "GET",
url: "cmn_pg.php?page="+page,
success: function(ccc)
{
pag("#search_results").html(ccc);
}
});
Or
pag.ajax
({
type: "post",
url: "cmn_pg.php",
data: {'data':dataString},//You can add as many datas seperated by comma to pass more values
success: function(ccc)
{
pag("#search_results").html(ccc);
}
});
And in php
$dataString = $_POST['data'];
Upvotes: 0