CODEWITHSUNDEEP
pythonxsdschemalxml
user1610952
user1610952

Reputation: 1289

Is it possible to validate an XML file against XSD 1.1 in Python?

I want validate an XML file against an XSD file using lxml.XMLSchema. But the problem is the XSD is in 1.1. So it doesn't work.

This is a part of the XML:

<?xml version="1.0" encoding="UTF-8"?>
<dictionary xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xsi:noNamespaceSchemaLocation="!!assert.xsd">
  <SizeType>10</SizeType>
</dictionary>

And this is its XSD file:

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           elementFormDefault="qualified">
  <xs:element name="SizeType">
    <xs:simpleType>
      <xs:restriction base="xs:integer">
        <xs:assertion test="$value = 10"/>
      </xs:restriction>
    </xs:simpleType>
  </xs:element>
</xs:schema>

So, is it possible to validate an XML file against a XSD file that uses xs:assertion statements (1.1)?

I think this question is closely related to this: lxml with schema 1.1

Upvotes: 7

Views: 3547

Answers (2)

kjhughes
kjhughes

Reputation: 111541

2022 update

Yes, starting in 2019 it finally became possible to validate XML against XSD 1.1 in Python.

Davide Brunato added XSD 1.1 support to xmlschema (v1.0.14).

Thanks to @Alex for pointing out the update.

2013 original answer

As of early November 2013, only the following XML processors support XSD 1.1:

There is no XML parser written in Python that validates against XSD 1.1 yet.

Upvotes: 2

Shlomo Gottlieb
Shlomo Gottlieb

Reputation: 593

xmlschema (1.0.14+) supports XSD 1.1

https://pypi.org/project/xmlschema

Upvotes: 3

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