Reputation: 3405
How do I merge 2 lists in such a way that the resulting list contains the elements of 2 lists in alternating fashion in Scala.
Input:
val list1 = List("Mary", "a", "lamb")
val list2 = List("had", "little")
Output:
List("Mary", "had", "a", "little", "lamb")
Upvotes: 13
Views: 5233
Reputation: 958
val list1 = List("Mary", "a", "lamb")
val list2 = List("had", "little")
def merge1(list1: List[String], list2: List[String]): List[String] = {
if (list1.isEmpty) list2
else list1.head :: merge(list2, list1.tail)
}
def merge2(list1: List[String], list2: List[String]): List[String] = list1 match {
case List() => list2
case head :: tail => head :: merge(list2, tail)
}
merge1(list1, list2)
merge2(list1, list2)
//> List[String] = List(Mary, had, a, little, lamb)
Upvotes: 5
Reputation: 20992
What you're looking for is usually called "intersperse" or "intercalate" and there are a few ways to do it:
def intersperse[A](a : List[A], b : List[A]): List[A] = a match {
case first :: rest => first :: intersperse(b, rest)
case _ => b
}
You can also use scalaz
import scalaz._
import Scalaz._
val lst1 = ...
val lst2 = ...
lst1 intercalate lst2
Edit: You can also do the following:
lst1.zipAll(lst2,"","") flatMap { case (a, b) => Seq(a, b) }
Come to think of it, I believe the last solution is my favorite since it's most concise while still being clear. If you're already using Scalaz, I'd use the second solution. The first is also very readable however.
And just to make this answer more complete, adding @Travis Brown's solution that is generic:
list1.map(List(_)).zipAll(list2.map(List(_)), Nil, Nil).flatMap(Function.tupled(_ ::: _))
Upvotes: 21
Reputation: 134
You could do something like this:
def alternate[A]( a: List[A], b: List[A] ): List[A] = {
def first( a: List[A], b: List[A] ): List[A] = a match {
case Nil => Nil
case x :: xs => x :: second( xs, b )
}
def second( a: List[A], b: List[A] ): List[A] = b match {
case Nil => Nil
case y :: ys => y :: first( a, ys )
}
first( a, b )
}
Upvotes: 1
Reputation: 33657
list1.zipAll(list2,"","").flatMap(_.productIterator.toList).filter(_ != "")
Upvotes: 1