rs19
rs19

Reputation: 667

how do i hide the brackets and commas from the print statement?

i'm trying to format this better so it prints out as one block of text (spaces are ok)

right now it's printing like this [4444, 4444] and i want it to print 4444 4444

#secret code encrypter 

def encoder(plain):
    '''encodes a given input with a secret formula
    '''
    result = []

    for i in plain:
        i=ord(i)*77+4
        result.append(i)

    return result 

def main():

    plain=input('Enter a sentence: ')
    final=encoder(plain)

    print(final)

main()

Upvotes: 0

Views: 311

Answers (5)

Jon Clements
Jon Clements

Reputation: 142136

Make them strings and join them:

print(' '.join(map(str, your_list)))

Even better (if you're using Python 3.x) to avoid explicit conversion:

print(*your_list)

Upvotes: 7

UpAndAdam
UpAndAdam

Reputation: 5467

Borrows from what others pointed out from my comments adds something many have missed that was previously in one of the answers:

  1. (For pre python 3.0:) You will want to use raw_input instead of input because you just want to capture not evaluate.
    Per 2.7.5 docs:

    input(prompt) is equivalent to eval(raw_input(prompt))

  2. Printing ( mostly lifted from Jon C's answer) Make them strings and join them:

    print(' '.join(map(str, your_list)))
    

    Even better (if you're using Python 3.x) to avoid explicit conversation:

    print(*your_list)
    

Upvotes: 0

Mark Ransom
Mark Ransom

Reputation: 308130

Based on your comment to an earlier answer, you need this:

print(' '.join(str(x) for x in final))

This converts each of the elements in final to a string before joining them with a space between.

Upvotes: 2

reem
reem

Reputation: 7236

Try this: print(" ".join(list_you_want_to_print))

str.join(iterable) will return a string with the items in the utterable separated by the string.

Upvotes: 1

Linuxios
Linuxios

Reputation: 35793

If I get what your trying to do, try this:

print(" ".join(map(str, final)))

Upvotes: 4

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