CODEWITHSUNDEEP
c++randomoutputsleepsrand
Einārs Leckis
Einārs Leckis

Reputation: 3

How to set time to output numbers by difference 1 second

I have a program like this:

using namespace std;

int main()
{
    srand(time());
    int izlases_sk, a, b, c, d, e;
    cout << "Enter 5 numbers" << endl;
    cin >> a;
    cin >> b;
    cin >> c;
    cin >> d;
    cin >> e;
    cout << endl;

    for (int x = 0; x < 20; x++)
    {
        izlases_sk = rand() % 77;
        cout << izlases_sk << "\t";
        if( izlases_sk == a || izlases_sk == b || izlases_sk == c || izlases_sk == d || izlases_sk == e)
            cout << " You predicted this number!\t";
        else
            cout << "No\t";
        {
            if (a > 77 || b > 77 || c > 77 || d > 77 || e > 77)
                goto end;
        }
        if ((x + 1) % 5 == 0)
            cout<<endl;
    }
    end:
    getch ();
}

I want that my randomly generated numbers get outputted one by one with 1 second delay in between. How can I do it?

Example: c++ generate 76, then after one second he generates next number.

Upvotes: 0

Views: 254

Answers (2)

Felix Glas
Felix Glas

Reputation: 15524

If you're using a C++11 compliant compiler then simply insert the following line wherever you want the program to sleep for a second (you need headers <thread> and <chrono>):

std::this_thread::sleep_for(std::chrono::seconds(1));

Also this code is portable.

Upvotes: 1

twoflower
twoflower

Reputation: 6830

Use the Sleep function (The Windows and the Linux version)

Upvotes: 2

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