CODEWITHSUNDEEP
javajakarta-eeweblogic-10.x
GabrielBB
GabrielBB

Reputation: 2679

weblogic.descriptor.DescriptorException: Unmarshaller failed

When i deploy my WAR in Weblogic 10.3.6 it runs but in weblogic 10.3.0 it throws this:

Unable to load descriptor D:\bea103\user_projects\domains\SRVWinplex\Deployments\WinplexAdmin.war/WEB-INF/weblogic.xml of module WinplexAdmin.war. The error is weblogic.descriptor.DescriptorException: Unmarshaller failed at weblogic.descriptor.internal.MarshallerFactory$1.createDescriptor(MarshallerFactory.java:152) at weblogic.descriptor.BasicDescriptorManager.createDescriptor(BasicDescriptorManager.java:306) at weblogic.application.descriptor.AbstractDescriptorLoader2.getDescriptorBeanFromReader(AbstractDescriptorLoader2.java:788) at weblogic.application.descriptor.AbstractDescriptorLoader2.createDescriptorBean(AbstractDescriptorLoader2.java:409) at weblogic.application.descriptor.AbstractDescriptorLoader2.loadDescriptorBeanWithoutPlan(AbstractDescriptorLoader2.java:759) at weblogic.application.descriptor.AbstractDescriptorLoader2.loadDescriptorBean(AbstractDescriptorLoader2.java:768) at weblogic.servlet.internal.WebAppDescriptor.getWeblogicWebAppBean(WebAppDescriptor.java:170)

It's a problem with the weblogic.xml i guess. This is my weblogic.xml(Without basic tags) :

<jsp-descriptor>
    <keepgenerated>true</keepgenerated>
    <debug>true</debug>
</jsp-descriptor>
<context-root>/WinplexAdmin</context-root>
<library-ref>
    <library-name>jsf</library-name>
    <specification-version>2.0</specification-version>
    <implementation-version>1.0.0.0_2-0-2</implementation-version>
</library-ref>
<container-descriptor>
    <prefer-web-inf-classes>true</prefer-web-inf-classes>
</container-descriptor>

What can be the problem here ?

Upvotes: 3

Views: 29502

Answers (4)

Ajin Vijay
Ajin Vijay

Reputation: 1

If you have tried with the solutions below and still not working, it may due to version mismatches in JavaVersion, try

  1. Click on Windows
  2. Click on Preferences.
  3. Click on Java->Compiler. Check whether it is matching with the version you use in the application. Change the compiler compliance level if not matched

Upvotes: 0

GabrielBB
GabrielBB

Reputation: 2679

Solved. I was compiling with a newer weblogic.jar I mean: I had Weblogic 10.3.6 attached to NetBeans, so it was a different weblogic.xml.

A correct weblogic.xml for Weblogic 10.3.0 is like this:

<weblogic-web-app xmlns="http://www.bea.com/ns/weblogic/weblogic-web-app" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.bea.com/ns/weblogic/weblogic-web-app http://www.bea.com/ns/weblogic/weblogic-web-app/1.0/weblogic-web-app.xsd">

You can see "http://www.bea.com/" in the xml while a weblogic.xml for Weblogic 11g and etc. has links with "java" or "sun" in it.

I just downloaded Weblogic 10.3.0, attached it to NetBeans, change the server for the project from Weblogic 10.3.6 to 10.3.0 and then re-compile.

Or... the easy way is just replacing the weblogic.xml code for the one i pasted here and compile.

I hope it solves your problem.

Upvotes: 3

manohar e
manohar e

Reputation: 327

If the above code is not for you then you can use below one 

<web-app xmlns="http://java.sun.com/xml/ns/j2ee" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">

Upvotes: 0

ronenfe
ronenfe

Reputation: 2405

If you use Sun XML Parser and not the default Weblogic XML parser this is what happening:

The problem is that the Sun parser fail to parse the web.xml of the apps if in this element: 

<web-app version="2.5" metadata-complete="true" xmlns="http://java.sun.com/xml/ns/javaee"

                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

                xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

xmlns attribute is after xmlns:xsi attribute.

xmlns attribute must be before xmlns:xsi attribute!

Took me very long time to find it.

Upvotes: 0

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