Bash array contents get printed in columns

Question

$declare -a inputs=("(1 3 4 8 6 2 7 0 5)" "(2 8 1 0 4 3 7 6 5)"

$ for i in ${inputs[@]}; do echo $i; done;

gives

(1
3
4
8
6
2
7
0
5)
(2
8
1
0
4
3
7
6
5)

I want each array in a row.

Answer 1

Use quotes:

for i in "${inputs[@]}"; do echo "$i"; done;
(1 3 4 8 6 2 7 0 5)
(2 8 1 0 4 3 7 6 5)

Answer 2

You need to use quotes. Say:

for i in "${inputs[@]}"; do echo $i; done

This would return:

(1 3 4 8 6 2 7 0 5)
(2 8 1 0 4 3 7 6 5)

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Moreover, remove the ; after done unless it's the last line in your script!