Reputation: 31
I have an xml of the following form
<operation>
<update>
<wogroup>id1</wogroup>
<woid>SL0001</woid>
<status>NEW</status>
</update>
<update>
<wogroup>id1</wogroup>
<woid>SL0001</woid>
<status>OPEN</status>
</update>
<update>
<wogroup>id1</wogroup>
<woid>SL0001</woid>
<status>CLOSED</status>
</update>
<update>
<wogroup>id1</wogroup>
<woid>SL0002</woid>
<status>NEW</status>
</update>
<update>
<wogroup>id2</wogroup>
<woid>SL00011</woid>
<status>OVERRIDE</status>
</update>
<update>
<wogroup>id2</wogroup>
<woid>SL00011</woid>
<status>CLOSED</status>
</update>
<update>
<wogroup>id2</wogroup>
<woid>SL00021</woid>
<status>NEW</status>
</update>
</operation>
I have no saying on how the xml looks like, but I need to make a report in html. I would like to see an html like
Group : id1
WO : SL001
NEW
OPEN
CLOSED
WO : SL002
NEW
Group : id2
WO : SL0011
OVERRIDE
CLOSED
WO : SL0021
NEW
I succeed in grouping on wogroup or woid, but not in a nested way ... anyone a suggestion?
Upvotes: 3
Views: 953
Reputation: 1278
I don't know if this is the best way but it groups elements as you need:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" encoding="UTF-8" />
<xsl:key name="updates-by-wogroup" match="/operation/update" use="wogroup" />
<xsl:key name="updates-by-wogroup-and-woid" match="/operation/update" use="concat(wogroup,woid)" />
<xsl:template match="/">
<xsl:for-each select="operation/update[not(wogroup = preceding-sibling::update/wogroup)]">
Group: <xsl:value-of select="wogroup" />
<xsl:for-each select="key('updates-by-wogroup',current()/wogroup)[not(woid = preceding-sibling::update/woid)]">
WO: <xsl:value-of select="woid" />
<xsl:for-each select="key('updates-by-wogroup-and-woid',concat(current()/wogroup,current()/woid))">
<xsl:text>
<xsl:value-of select="status" /></xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
If you succeeded in grouping by wogroup or woid you will understand the code, anyway ask any question if you need.
Upvotes: 2