CODEWITHSUNDEEP
phpdatetimestampstrtotime
Muhammad Arslan Jamshaid
Muhammad Arslan Jamshaid

Reputation: 1197

strtotime conversion with variable error

I am getting wrong output i.e. 1194908400 None of this is working i.e. I tried to put double quotes around variable, tried without quotation marks. result is same and wrong.

$d='07-11-13';
echo $d;
echo strtotime($d);
echo "<br>";
echo strtotime("$d");

Upvotes: 0

Views: 201

Answers (4)

Styphon
Styphon

Reputation: 10447

The problem is you need to specify a 4 digit year, so that strtime can fully work out which date format you are using. With 07-11-13 it probably thinks you are using 2007-11-13.

Change it to 07-11-2013 and you will get the correct answer.

Upvotes: 0

briosheje
briosheje

Reputation: 7446

After a few checks, the error is actually NOT in the format you're passing, but rather on the way you're passing it.

What you should do is just replace "13" with "2013":

strtotime("07-11-2013");

output: 1383778800

echo strtotime("2013-11-07");

output: 1383778800

echo strtotime('07-11-13');

output: 1194908400

Upvotes: 1

AbraCadaver
AbraCadaver

Reputation: 78994

strtotime() will accept:

m/d/y
d-m-y

With / it expects month/day and with - it expects day-month.

Upvotes: 0

Zahidul Hossein Ripon
Zahidul Hossein Ripon

Reputation: 672

$d='07-11-13' is wrong, Try this

$d='2013-11-13';
echo $d;
echo strtotime($d);
echo "<br>";
echo strtotime("$d")

Upvotes: 0

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