CODEWITHSUNDEEP
androidjsonhttpgetconnection
Thomas Trabelsi
Thomas Trabelsi

Reputation: 330

GET request JSONObject android

i did a simple GET request, who return 1 or 0 if my login & password are correct. I do my connection on an other thread .

Like this : 

public void getConnection(){

    String url = null;

    url = NOM_HOTE + PATH_METHODE + "identifiant="+ identifiant.getText().toString() + "&password="+ password.getText().toString();

     HttpClient httpClient = new DefaultHttpClient();

     try{
         HttpGet httpGet = new HttpGet(url);
         HttpResponse httpResponse = httpClient.execute(httpGet);
         HttpEntity httpEntity = httpResponse.getEntity();

         if(httpEntity != null){


             InputStream inputStream = httpEntity.getContent();

             //Lecture du retour au format JSON
             BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
             StringBuilder stringBuilder = new StringBuilder();

             String ligneLue = bufferedReader.readLine();
             while(ligneLue != null){
                 stringBuilder.append(ligneLue + " \n");
                 ligneLue = bufferedReader.readLine();
             }
             bufferedReader.close();

             JSONObject jsonObject = new JSONObject(stringBuilder.toString());

             Log.i("Chaine JSON", stringBuilder.toString());   


             JSONObject jsonResultSet = jsonObject.getJSONObject("nb"); <--it's here where the error occured

//               int nombreDeResultatsTotal = jsonResultSet.getInt("nb");
//               Log.i(LOG_TAG, "Resultats retourne" + nombreDeResultatsTotal);    

         }// <-- end IF          
     }catch (IOException e){
         Log.e(LOG_TAG+ "1", e.getMessage());
     }catch (JSONException e){
         Log.e(LOG_TAG+ "2", e.getMessage());

     }
}

i have a JSON return like this : {"nb":"1"} or {"nb":"0"} So my JSON is correct. but i have this error on catch(JSONException) when i submit my form :

11-07 17:01:57.833: E/ClientJSON2(32530): Value 1 at nb of type java.lang.String cannot be converted to JSONObject

i don't understand why , whereas my syntax, connection are correct and on the Log with tag "Chaine JSON" , i have {"nb:"1"} in the response..

Upvotes: 2

Views: 4690

Answers (3)

Damien R.
Damien R.

Reputation: 3373

Use 

String myReturnValue = jsonObject. getString("nb");

instead of 

JSONObject jsonResultSet = jsonObject.getJSONObject("nb");

This will return you a String ;)

Upvotes: 0

Rohit5k2
Rohit5k2

Reputation: 18112

value represented by "nb" is a string not object.

use jsonObject.getString("nb"); even jsonObject.getInt("nb"); would work if value is a numerical

Upvotes: 0

Blackbelt
Blackbelt

Reputation: 157467

nb is a String, not a JSONObject. Change

JSONObject jsonResultSet = jsonObject.getJSONObject("nb");

in

String result = jsonObject.getString("nb");

Upvotes: 5

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