CODEWITHSUNDEEP
javascriptregex
Arnaud Weil
Arnaud Weil

Reputation: 2492

Regular expression match in JavaScript matches too much

I'm using this expression:

"g{field1}={field2}a".match(/{([^\{\}]+)\}/g)

What I need is to get "field1" and "field2", but it returns an array with "{field1}" and "{field2}".

Upvotes: 2

Views: 428

Answers (5)

RobG
RobG

Reputation: 147363

You can also do:

'g{field1}={field2}a'.split(/[{}]/).filter(function(a,i){return i%2;});

provided the string always contains matching "{}" pairs. There is also:

'g{field1}={field2}a'.split(/^[^{]*\{|\}[^{]*\{|\}[^{]*$/g).slice(1,-1);

both of which will work on any number of {…} pairs (0 to n).

Upvotes: 0

Ben
Ben

Reputation: 13615

You could use a lookahead

"g{field1}={field2}a".match(/[^\{\}]+(?=\})/g)

this will match any character that is not { or } if the matched set of characters is followed by a }

Upvotes: 1

plalx
plalx

Reputation: 43718

You can use exec which can return multiple capturing groups per matches.

var re = /{([^\{\}]+)\}/g,
    matches = [],
    input = "g{field1}={field2}a",
    match;

while (match = re.exec(input)) matches.push(match[1]);

console.log(matches);

You can also re-write your regex (here it depends what the input string can be):

var matches = "g{field1}={field2}a".match(/{([^}]+)}={([^}]+)}/).slice(1);

console.log(matches);

Upvotes: 3

Anto Jurković
Anto Jurković

Reputation: 11258

"g{field1}={field2}a".match(/([^g=a\{\}]+)/g)

returns

["field1", "field2"]

Upvotes: 0

Pranav Gupta
Pranav Gupta

Reputation: 944

If you just want an array without curly braces, you can use array map method:

"g{field1}={field2}a".match(/{([^\{\}]+)\}/g).map(function(i){return i.slice(1,-1)})

Upvotes: 2

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