CODEWITHSUNDEEP
cexception
user172632
user172632

Reputation:

Why a floating point exception

Just trying out some C on some of the project euler questions.

My question is why am I getting a floating point exception at run time on the following code?

#include <stdio.h>
main()
{
int sum;
int counter;

sum = 0;
counter = 0;

for (counter = 0; counter <= 1000; counter++)
{
    if (1000 % counter == 0) 
    {
        sum = sum + counter;
    }
}

printf("Hello World");
printf("The answer should be %d", sum);
}

Thanks,

Mike

Upvotes: 0

Views: 614

Answers (4)

AnT stands with Russia
AnT stands with Russia

Reputation: 320777

You are dividing 1000 by zero on the first iteration (calculating a reminder of something divided by 0). Why it crashed with a floating-point exception... I don't know. Maybe the compiler translated it into a floating-point operation. Maybe just a quirk of the implementation.

Upvotes: 2

Andy White
Andy White

Reputation: 88475

1000 % 0 is a division by zero

Upvotes: 1

Claudiu
Claudiu

Reputation: 229581

What happens when counter is 0? You try to compute 1000 % 0. You can't compute anything modulo 0, so you get an error.

Your if statement should read:

if (counter % 1000 == 0)

Upvotes: 0

avpx
avpx

Reputation: 1922

You start with counter = 0 and then do a "mod" with counter. This is a division by zero.

Hope this helps!

Upvotes: 6

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