CODEWITHSUNDEEP
c++compiler-errorsiteratorsyntax-errorstd
SKPS
SKPS

Reputation: 5836

C++11 : error: ‘begin’ is not a member of ‘std’

I am trying to do the following operation:

source = new int[10];
dest =  new int[10];
std::copy( std::begin(source), std::end(source), std::begin(dest));

However, the compiler reports the following error.

copy.cpp:5434:14: error: ‘begin’ is not a member of ‘std’
copy.cpp:5434:44: error: ‘end’ is not a member of ‘std’
copy.cpp:5434:72: error: ‘begin’ is not a member of ‘std’

I have included the required <iterator> header in the code. Can anybody help me on this?

Upvotes: 10

Views: 23090

Answers (3)

LocustOnMeadow
LocustOnMeadow

Reputation: 9

also have this problem when using g++ compiler this code in linux.

Using g++ compiler that contain C++ featuer should add C++11 flag

g++ -std=c++11 -o test test.cpp

Upvotes: -1

Vlad from Moscow
Vlad from Moscow

Reputation: 310950

Template functions std::begin() and std::end() are not implemented for pointers (pointers do not contain information about the number of elements they refer to) Instead them you should write

std::copy( source, source + 10, dest);

As for the error you should check whether you included header 

#include <iterator>

Also maybe your compiler does not support the C++ 2011 Standard.

Upvotes: 15

masoud
masoud

Reputation: 56479

In addition to include <iterator>in C++11 enabled compiler. You should know begin/end are not useful for pointers, they're useful for arrays:

int source[10];
int dest[10];

std::copy(std::begin(source), std::end(source), std::begin(dest));

Upvotes: 2

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