Richard
Richard

Reputation: 4546

Difference between jQuery.extend and jQuery.fn.extend?

I am trying to understand the jquery plugin syntax, because I want to merge two plugins into one. The blinker that also needs to be able to stop de interval or run a number of times.

Anyway, is this syntax the same as

jQuery.fn.extend({
    everyTime: function(interval, label, fn, times) {
        return this.each(function() {
            jQuery.timer.add(this, interval, label, fn, times);
        });
    },
    oneTime: function(interval, label, fn) {
        return this.each(function() {
            jQuery.timer.add(this, interval, label, fn, 1);
        });
    },

this

$.fn.blink = function(options)
    {

because it looks like the first(without =) is a way to set multiple methods at once. Is this right? Also while I am here What would be the reason to add the elements and some logic to the jquery object?

jQuery.extend({
    timer: {
        global: [],
        guid: 1,
        dataKey: "jQuery.timer",

(this is from the timer plugin)

Upvotes: 89

Views: 66022

Answers (5)

Dinesh
Dinesh

Reputation: 1134

jQuery.extend({
    abc: function(){
        alert('abc');
    }
});

usage: $.abc(). (No selector required like $.ajax().)

jQuery.fn.extend({
    xyz: function(){
        alert('xyz');
    }
});

usage: $('.selector').xyz(). (Selector required like $('#button').click().)

Mainly it is used to implement $.fn.each().

Upvotes: 83

Bergi
Bergi

Reputation: 664548

Difference between jQuery.extend and jQuery.fn.extend?

Actually, there is none apart from their base reference. In the jQuery source, you can read:

jQuery.extend = jQuery.fn.extend = function() { … };

So how does it work? The documentation reads:

Merges the contents of two or more objects together into the first object.

It's just a for-in-loop that copies properties, pimped up with a flag to recurse nested objects. And another feature:

If only one argument is supplied to $.extend(), this means the target argument was omitted

 // then the following will happen:
 target = this;

So if the function is called on jQuery itself (without explicit target), it will extend the jQuery namespace. And if the function is called on jQuery.fn (without explicit target), it will extend the jQuery prototype object where all the (plugin) methods are located.

Upvotes: 23

Shishir Arora
Shishir Arora

Reputation: 5923

$.fn.something= function{};

points to the jQuery.prototype and lets access dom elements through "this". Now u may use $(selector).something(); So this works as plugin function like $(selector).css();

$.something = function{};

adds a property or function to the jQuery object itself and u cannot use "this" for dom access Now u may use it as $.something(); this works as a utility function as $.trim()

but

$.fn.extend({function1(), function2()}) and  $.extend({function1(), function2()}) 

allows adding more than 1 function at the same time.Also they can be used to merge two object literals in case we provide more than one objects.

Upvotes: 10

gavenkoa
gavenkoa

Reputation: 48753

This blog post have nice description:

$.fn.extend({
myMethod: function(){...}
});
//jQuery("div").myMethod();

$.extend({
myMethod2: function(){...}
});
//jQuery.myMethod2();

Quotes:

As a general rule, you should extend the jQuery object for functions and the jQuery.fn object for methods. A function, as opposed to a method, is not accessed directly from the DOM.

Upvotes: 16

Philippe Leybaert
Philippe Leybaert

Reputation: 171794

jQuery.extend is used to extend any object with additional functions, but jQuery.fn.extend is used to extend the jQuery.fn object, which in fact adds several plugin functions in one go (instead of assigning each function separately).

jQuery.extend:

var obj = { x: function() {} }

jQuery.extend(obj, { y: function() {} });

// now obj is an object with functions x and y

jQuery.fn.extend:

jQuery.fn.extend( {
        x: function() {},
        y: function() {}
});

// creates 2 plugin functions (x and y)

Upvotes: 95

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