CODEWITHSUNDEEP
sqloracle-database
Hawk
Hawk

Reputation: 5170

divide a column into two based on another column value - ORACLE

First, hope the title expresses the issue. Otherwise, any suggest is welcomed. My issue is I have the following table structure: 

+----+------+------------------+-------------+
| ID | Name | recipient_sender |  user       |
+----+------+------------------+-------------+
|  1 | A    |                1 | X           |
|  2 | B    |                2 | Y           |
|  3 | A    |                2 | Z           |
|  4 | B    |                1 | U           |
|    |      |                  |             |
+----+------+------------------+-------------+

Whereby in the column recipient_sender the value 1 means the user is recipient, the value 2 means the user is sender.
I need to present data in the following way:

+----+------+-----------+---------+
| ID | Name | recipient |  sender |
+----+------+-----------+---------+
|  1 | A    | X         | Z       |
|  2 | B    | U         | Y       |
+----+------+-----------+---------+

I've tried self-join but it did not work. I cannot use MAX with CASE WHEN, as the number of records is too big.

Note: Please ignore the bad table design as it's just a simplified example of the real one

Upvotes: 0

Views: 2414

Answers (4)

TechDo
TechDo

Reputation: 18659

Please try:

SELECT
  MIN(ID) ID
  Name, 
  max(case when recipient_sender=1 then user else null end) sender, 
  max(case when recipient_sender=2 then user else null end) recipient
From yourTable 
group by Name

Upvotes: 1

nabuchodonossor
nabuchodonossor

Reputation: 2060

Create new Table (with better struct):

insert into <newtable> as 
select distinct 
    id, 
    name, 
    user as recipient, 
    (select user from <tablename> where id = recip.id and name = recip.name) as sender
from <tablename> recip

sorry, have no oracle here.

Upvotes: 0

mucio
mucio

Reputation: 7119

maybe you can try this:

  select min(id) id, 
         name,
         max(decode(recipient_sender, 1, user, '')) sender,
         max(decode(recipient_sender, 2, user, '')) recipient
    from t
group by name

You can check a demo here on SQLFiddle.

Upvotes: 1

ogres
ogres

Reputation: 3690

You can select values with this query 

SELECT t.id,
       t.name,
       case
         when t.recipient_sender = 1 then
          t.user
         ELSE
          t2.user
       END as recipient,
       case
         when t.recipient_sender = 2 then
          t.user
         ELSE
          t2.user
       END as sender
  FROM your_table t
  JOIN your_table t2
    ON t.name = t2.name
   AND t.id != t2.id

after this query you can add DISTINCT keyword or GROUP them ...

this query is used to join tables with column NAME but if you have some identity for message , join tables using that ,

Upvotes: 0

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