CODEWITHSUNDEEP
java
cbass0
cbass0

Reputation: 21

How can I display the output for this?

I am using a file that has a first and last name and four sales numbers. I have an array created. I want to use all the people and sales figures to be displayed. Here is the format of the file.

Willow Mary
154 189.5 95 76 63.51

Here's is what I was trying. It keeps going to my catch block. 

import java.io.File;
import java.util.Scanner;


public class Assignment10 {
    public static final int NUM_SALESPEOPLE = 20;

    public static void main(String[] args) {

        SalesPerson[] list = new SalesPerson[NUM_SALESPEOPLE];

        try {
            int people = 0;
            Scanner fileInput = new Scanner(new File("A10.txt"));

            while (fileInput.hasNext()) {
                String firstName = fileInput.nextLine();
                String lastName = fileInput.nextLine();
                double firstSales = fileInput.nextDouble();
                double secondSales = fileInput.nextDouble();
                double thirdSales = fileInput.nextDouble();
                double fourthSales = fileInput.nextDouble();

                SalesPerson person = new SalesPerson(firstName, lastName,
                        firstSales, secondSales, thirdSales, fourthSales);
                list[people] = person;
                people++;

            }
        } catch (Exception ex) {
            System.out.println("Error opening file.");
        }

Upvotes: 0

Views: 52

Answers (2)

Ted Hopp
Ted Hopp

Reputation: 234807

If your file is the format that you say, you are reading too many lines when you read each person. This code:

String firstName = fileInput.nextLine();
String lastName = fileInput.nextLine();

reads two lines from the file, yet the name appears on a single line. You are probably running out of lines when you get within three lines of the end of the file or else (more likely) trying to parse a line containing a name as if it were double values.

You also need to consume any trailing white space (including the newline) after reading the doubles. Try fileInput.skip("\\w");.

Instead, read the entire line of doubles as a single line and break it apart with code (e.g., using split(" ")) or by parsing in some other way.

Upvotes: 2

fvu
fvu

Reputation: 32953

This code

String firstName = fileInput.nextLine();
String lastName = fileInput.nextLine();

eats up 2 lines, so the following nextDouble() calls wont go where you want them to go.

Also

    } catch (Exception ex) {
        System.out.println("Error opening file.");
    }

Is not always true, because you catch all Exception's not only the ones that are file related. At the very least also output the message your Exception is generating:

    } catch (Exception ex) {
        System.out.println("Something went wrong: " + ex.getMessage() );
    }

Better still, catch all kinds of Exceptions generated in your program separately and provide a sensible error message, or recovery behavior per Exception type.

Upvotes: 0

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