Reputation: 195
I was making a program that will print out the periodic table with [ ]
for an element, and [*]
for the element you're searching for...
void printmap(int x, int y)
{
int a, b, table[9][18] = {
1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1,
1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1,
1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0,
0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0
}; // 0 - Empty, 1 - [ ], 2 - [*]
table[x][y] = 2;
b = 0;
printf("\n*******************\n\n");
for( a = 1, printf(" \t"); a < 19; a++)
{
printf("%3d", (b + a));
}
printf("\n");
for(a = 0; a < 9; a++)
{
printf("\n%2d\t", a + 1);
for(b = 0; b < 18; b++)
{
switch(table[a][b])
{
case 0 :
printf(" ");
case 1 :
printf("[ ]");
break;
case 2 :
printf("[*]");
break;
default :
printf("");
}
}
}
}
For some reason, the output is messed up... ( If I pass the argument for helium, which should be 0
and 18
this is what I get : http://pastebin.com/YjhjzSi8
What am I doing wrong? Thank you
Upvotes: 0
Views: 94
Reputation: 4444
As the other respondents have said, you need to initialize your table array correctly.
Also, you have missed a "break" in your switch/case statemet, and you also missed printing a newline at the end of each row. I took the liberty of renaming your variables a,b to row,col and fixed your code, this should do what you want,
void printmap(int x, int y)
{
int row=0, col=0;
int was = table[x][y];
table[x][y] = 2;
col = 0;
printf("\n*******************\n\n");
printf(" \t");
row=0; //you were not initializing row
for( col = 0; col < 18; col++)
{
printf("%3d", (col+row+1));
}
printf("\n");
for(row = 0; row < 9; row++)
{
printf("\n%2d\t", row + 1);
char* rc = " ";
for(col = 0; col < 18; col++)
{
switch(table[row][col])
{
case 0 : rc=(" "); break; //was missing break
case 1 : rc=("[ ]"); break;
case 2 : rc=("[*]"); break;
default: rc=(" "); break; //was missing break
}
printf("%s",rc);
}
printf("\n"); //missing print newline
}
table[x][y] = was;
}
And here is the table, as others have suggested,
int table[9][18] = {
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1 },
{ 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1 },
{ 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1 },
{ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 },
{ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 },
{ 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 },
{ 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 },
{ 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0 },
{ 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0 }
}; // 0=Empty, 1=[ ], 2=[*]
Upvotes: 2
Reputation: 3752
Been a while since I used C++, but, this is not how you initialize a 2D array. In fact I'm surprised it even compiles. Correct way is something like:
table[0] = {1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1};
table[1] = {1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1};
table[2] = {1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1};
...
Another example: 2D array values C++
Upvotes: 2
Reputation: 209062
That's not a 2D array, just because you make it LOOK like a 2D array, doesn't mean it is one.
This what you have
table[9][18] = {
1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1,
1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1,
...
0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0
};
You should add more brackets accordingly
table[9][18] = {
{1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1),
....
{0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0}};
Upvotes: 2