CODEWITHSUNDEEP
php
Web Worm
Web Worm

Reputation: 2066

php time difference script problem

here is my php code.....

<?php
function nicetime($date)
{
    if(empty($date)) {
        return "No date provided";
    }

    $periods         = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
    $lengths         = array("60","60","24","7","4.35","12","10");

    $now             = time();
    $unix_date  = strtotime($date);

       // check validity of date
    if(empty($unix_date)) {    
        return "Incorrect Date";
    }

    // is it future date or past date
    if($now > $unix_date) {    
        $difference     = $now - $unix_date;
        $tense         = "ago";

    } else {
        $difference     = $unix_date - $now;
        $tense         = "ago";
    }

    for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
        $difference /= $lengths[$j];
    }

    $difference = round($difference);

    if($difference != 1) {
        $periods[$j].= "s";
    }

    return "$difference $periods[$j] {$tense}";
}
?>

but it is not showing the time correctly....and if any current time is given to it is showing 25-35 seconds ago and so on....but i want to make a time difference funtion like digg.com in a format like 2 Mints AND 3 Sec ago... how can i do that

Upvotes: 0

Views: 348

Answers (2)

Geert
Geert

Reputation: 1814

Have a look at and learn from the Date::span and Date::fuzzy_span methods of the Kohana Date class.

Upvotes: 0

hsz
hsz

Reputation: 152206

Try it to do with the other way - at the beginning multiply all $lengths values (i.e. $multiplied).
1. Divide $difference with that value.
2. If >= 1 then you have a solution.
Else divide $multiplied with the array_pop($lengths) value. Go to 2.
3. You have the solution.

I think it would be it.

BTW - $tense is always "ago".

Upvotes: 1

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