kiri
Reputation: 2642
How to get the filepath of a ZipFile object?
If I have a zipfile.ZipFile object, how can I determine the file path of the zip file from the object?
a = zipfile.ZipFile('C:\\path\\zipfile.zip')
a.get_file_path()
where get_file_path() should return 'C:\\path\\zipfile.zip'.
Upvotes: 7
Views: 6221
Answers (1)
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