Python BeautifulSoup findAll by "class" attribute

Question

I want to do the following code, which is what BS documentation says to do, the only problem is that the word "class" isn't just a word. It can be found inside HTML, but it's also a python keyword which causes this code to throw an error.

So how do I do the following?

soup.findAll('ul', class="score")

Answer 1

If OP is interested in getting the finalScore by going through ul you could solve this with a couple of lines of gazpacho:

from gazpacho import Soup

html = """\
<div>
    <ul class="score header" id="400488971-linescoreHeader" style="display: block">
      <li>1</li>
      <li>2</li>
      <li>3</li>
      <li>4</li>
      <li id="400488971-lshot"> </li>
      <li class="finalScore">T</li>
    </ul>
<div>
"""

soup = Soup(html)
soup.find("ul", {"class": "score"}).find("li", {"class": "finalScore"}).text

Which would output:

'T'

Answer 2

Your problem seems to be that you expect find_all in the soup to find an exact match for your string. In fact:

When you search for a tag that matches a certain CSS class, you’re matching against any of its CSS classes:

You can properly search for a class tag as @alKid said. You can also search with the class_ keyword arg.

soup.find_all('ul', class_="score")

Answer 3

Here is how to do it:

soup.find_all('ul', {'class':"score"})