Reputation: 25584
I'm getting some trouble to find a regular expression to find a phone number in this format that allways start with the number "9" in the middle of a text:
90 00 00 000
I can find a number with this regular expression:
phones= re.findall(r'(\d{2})\D+(\d{2})\D+(\d{2})\D+(\d{3})', "55 66 66 778 xcvxcvxv 94 44 44 456")
print phones
> [('55', '66', '66', '778'), ('94', '44', '44', '456')]
But I need to find only the number started witn "9". How can I do this?
Best Regards,
Upvotes: 0
Views: 1079
Reputation: 4795
You can just change the first \d{2}
to 9\d
, however I'd recommend also changing it to match whitespace rather than non-numeric characters in between digits.
(9\d)\s+(\d{2})\s+(\d{2})\s+(\d{3})
Upvotes: 2