CODEWITHSUNDEEP
javaexceptionbuffer
user2441441
user2441441

Reputation: 1387

How to avoid BufferUnderflowException

I'm using this function to convert bytearray to int. 

public static int byteArrayToInt(byte[] b) {
    ByteBuffer bb = ByteBuffer.wrap(b);
    bb.order(ByteOrder.LITTLE_ENDIAN);
    return bb.getInt();
}

Unfortunately I'm getting java.nio.BufferUnderflowException at the return statement. I'm calling this function many times by the way. I read that it happens when more bytes are being read than the buffer size. But can anyone tell me how to avoid it?

Is there a way to copy my original bytearray to new bytearray of size 4 and pass this bytearray to the function?

UPDATE: I tried this in main method: 

byte[] bbTemp=new byte[4];
bbTemp = originalbyteArray;

And passed bbTemp to the above function, but it doesn't work. Any idea why?

Upvotes: 0

Views: 4667

Answers (1)

Sotirios Delimanolis
Sotirios Delimanolis

Reputation: 280168

A BufferUnderflowException will be thrown

If there are fewer than four bytes remaining in this buffer

Make sure your byte[] has at least 4 bytes in it, which is the size of an int.

Upvotes: 3

Related Questions