CODEWITHSUNDEEP
javanumbersjava.util.scanner
Arc
Arc

Reputation: 449

Java scanner, containing numbers

String[] invalidChars = {"0", "1", "2", "3", "4", "5", "6", "7", "8", "9"};
         Scanner sc = new Scanner(System.in);
         try {
             String country = sc.next();
             String state = sc.next();
             String city = sc.next();

             if(country.contains(invalidChars) || state.contains(invalidChars) || city.contains(invalidChars)) {

             }
         }
         catch(Exception e){}

How would I tell an if statement to check if a string contains any number? I tried the array buy I get an error saying that "String[] cannot be converted to CharSequence"? Any ideas please?

Upvotes: 1

Views: 140

Answers (2)

frankie liuzzi
frankie liuzzi

Reputation: 1720

You want to use a regex.

yourString.matches(".*\\d.*");  // returns true if the string contains a number

Upvotes: 1

noone
noone

Reputation: 19776

The most straight-forward in your scenario would be to iterate through your invalid characters, one by one.

for (String invalidChar : invalidChars) {    
    if(country.contains(invalidChar ) || state.contains(invalidChar ) || city.contains(invalidChar )) {

    // do something
    break;
    }    
}

A cleaner way would be to use a regular expression checking for a match on [0-9].

Upvotes: 1

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