Reputation: 2618
This is the example code I have:
#include <iostream>
#include <vector>
#include <string>
class Animal {
};
class Rabbit : public Animal {
};
class Caller {
public:
virtual void call(Animal* a) {
std::cout << "Caller calls animal" << std::endl;
}
virtual void call(Rabbit* r) {
std::cout << "Caller calls rabbit" << std::endl;
}
};
int main(int argc, char** argv) {
std::vector<Animal*> v;
Caller c;
auto a = new Animal();
auto r = new Rabbit();
v.push_back(a);
v.push_back(r);
for(auto elem : v) {
c.call(elem);
}
return 0;
}
The output of this code can be found here
and it outputs:
Caller calls animal
Caller calls animal
I'm wondering, without casting a specific element to Rabbit*
, is there a way to get call(Rabbit *r)
method to get called?
Upvotes: 0
Views: 82
Reputation: 153840
Sure, e.g., by jumping through a suitable visitor in your system of polymorphic classes. I think you'll need to use two names instead of call()
, however. I used pubCall()
and call()
.
#include <iostream>
#include <vector>
#include <string>
class Visitor;
class Animal {
public:
virtual void visit(Visitor&);
};
class Rabbit : public Animal {
void visit(Visitor&);
};
class Visitor
{
public:
virtual void call(Animal* a) = 0;
virtual void call(Rabbit* r) = 0;
};
void Animal::visit(Visitor& v) {
v.call(this);
}
void Rabbit::visit(Visitor& v) {
v.call(this);
}
class Caller
: Visitor {
public:
void pubCall(Animal* a) { a->visit(*this); }
private:
virtual void call(Animal* a) {
std::cout << "Caller calls animal" << std::endl;
}
virtual void call(Rabbit* r) {
std::cout << "Caller calls rabbit" << std::endl;
}
};
int main(int argc, char** argv) {
std::vector<Animal*> v;
Caller c;
auto a = new Animal();
auto r = new Rabbit();
v.push_back(a);
v.push_back(r);
for(auto elem : v) {
c.pubCall(elem);
}
return 0;
}
Upvotes: 3