Reputation: 3927
Hey all, I was wondering if any knew of a way to use a regular expression or wildcard operator (or pehaps '%LIKE%'
in SQL) so I could use JSONPath to do searching within a large set of JSON data.
For instance (and yes, I'm parsing, not eval( )
ing my data in the app):
var obj = eval ( '({ "hey": "can you find me?" })' );
And I'd like to be able to look through the data like this:
$.[?(@.hey:contains(find))] // (in jQuery terminology)
where the contents of an argument is part or all of the value in the { "key" : "value" }
pairs in my data.
At the moment I have only found documentation on >
, <
, =
, and !=
relational operators, which don't give me that much flexibility.
Does anyone know a way I can just just JSONPath to find this data (without having to loop through all the entries)?
I don't want to use Dojo's JSONQuery, as this would require another library. However, it lets you do this, here their example:
[?description~‘*the*’]
Ask me if you want more clarification of the question.
Upvotes: 17
Views: 51035
Reputation: 340
You can use LIKE in jsonpath this way:
$.[?(@.hey like_regex '.*find.*')]
Upvotes: -1
Reputation: 105
Also, may be it will be useful for someone. Link to JSONPath Notation
It works for me (JMeter 4.0)
=~
Match a JavaScript regular expression. For example, [?(@.description =~ /cat.*/i)] matches items whose description starts with cat (case-insensitive).
Upvotes: 8
Reputation: 159
If anyone wants the contains solution in Java then this works with JsonPath
Filter<?> filter = Filter.filter(Criteria.where("hey").regex(Pattern.compile(".*find.*")));
System.out.println(JsonPath.read(json, "$..[?]", filter));
Imports
import com.jayway.jsonpath.Criteria;
import com.jayway.jsonpath.Filter;
import com.jayway.jsonpath.JsonPath;
Upvotes: 4
Reputation: 3927
nevermind, guys, found a way to do it by just using ECMA inside of JSONPath, though this is not a native selector / operator. Simply used:
$.[?(/find/.test(@.hey))]
the RegExp test( ) method (which JSONPath eval
s behind the scenes).
If anyone has a better answer, though, let me know.
Upvotes: 27