CODEWITHSUNDEEP
phpemail
Chris Lad
Chris Lad

Reputation: 349

PHP get the email that was filled in and send a message to that email?

So what I want to do is get the email they filled the forum in with and then send a message to that email they filled in here's what I have: it says its sent but I never get the message:

 <?php
       $name = $_POST['name'];
       $email = $_POST['email'];
       $message = $_POST['message'];
       $from = 'From: My Contact Form';
       $to = '$email';
       $subject = 'Folio Message';

       $body = "Hello";



       if ($_POST['submit']) {
           if (mail ($to, $subject, $body, $from)) {
           echo '<center><font color="lightgray"><p>Message Sent Successfully!</p><script type="text/javascript"> function leave() { window.location = "http://webdesign.about.com"; } setTimeout("leave()", 3000); </script></center>';
           } else {
           echo '<center><font color="lightgray"><p>Ah! Try again, please?</p></font></center>';
           }
       }
    ?>

So i have $to = '$email'; so by doing that it should read the email that was filled in right? Idk my PHP skills are weak any idea's? or advice? Thank you in advance kind people!

Upvotes: 0

Views: 67

Answers (3)

Troggy
Troggy

Reputation: 965

Two things here:

  1. From header should contain valid mail address. E.g.

    $from = 'From: [email protected]';

  2. As others said fix the single quotes. You can just use $email in mail call like

    mail ($email, $subject, $body, $from)

On a different note, consider sanitizing your POST parameters. Especially if your script is on publicly available site.

Upvotes: 0

neo
neo

Reputation: 164

Remove the apostrophes from the $to = '$email';

It should be $to = $email;

With the apostrophes, your $to variable is being set to the string "$email" and not the email that the user entered.

Upvotes: 1

elixenide
elixenide

Reputation: 44823

Drop the single quotes around $email, so your code looks like this: $to = $email;.

PHP evaluates content in single quotes as a literal string, without interpreting any variables. So, it is literally using the text $email as the recipient's email address.

Upvotes: 0

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